Complete Question: Which of the following is an example of the difference of two squares?
A x² − 9
B x³ − 9
C (x + 9)²
D (x − 9)²
Answer:
A. .
Step-by-step explanation:
An easy way to spot an expression that is a difference of two squares is to note that the first term and the second term in the expression are both perfect squares. Both terms usually have the negative sign between them.
Thus, difference of two squares takes the following form: .
a² and b² are perfect squares. Expanding will give us .
Therefore, an example of the difference of two squares, from the given options, is .
can be factorised as .
Answer:
B. y + 2 = ½(x + 3)
Step-by-step explanation:
Insert the coordinates into the formula with their CORRECT signs. Remember, in the Point-Slope Formula, <em>y</em><em> </em><em>-</em><em> </em><em>y</em><em>₁</em><em> </em><em>=</em><em> </em><em>m</em><em>(</em><em>x</em><em> </em><em>-</em><em> </em><em>x</em><em>₁</em><em>)</em><em>,</em><em> </em>all the negative symbols give the OPPOSITE term of what they really are.
Answer:
$128. Correct answer: $208. Explanation: (320) / (0.8) = 400. The couch has been marked down an additional 40% from the sale price of $320. $320 * 0.6 ... The next day, the store ran a sale of 20% off all items. What is the ... Explanation: 25% off means that the new price of the television will be 75% of the original price:.
Step-by-step explanation:
Evaluate abs(-4 b - 8) + abs(-b^2 - 1) + 2 b^3 where b = -2:
abs(-4 b - 8) + abs(-b^2 - 1) + 2 b^3 = abs(-4 (-2) - 8) + abs(-1 - (-2)^2) + (-2)^3×2
(-2)^2 = 4:
abs(-4 (-2) - 8) + abs(-4 - 1) + 2×(-2)^3
-4 (-2) = 8:
abs(8 - 8) + abs(-4 - 1) + 2×(-2)^3
8 - 8 = 0:
abs(0) + abs(-1 - 4) + 2×(-2)^3
-1 - 4 = -5:
abs(0) + abs(-5) + 2×(-2)^3
(-2)^3 = (-1)^3×2^3 = -2^3:
abs(0) + abs(-5) + 2×-2^3
2^3 = 2×2^2:
abs(0) + abs(-5) + 2 (-2×2^2)
2^2 = 4:
abs(0) + abs(-5) + 2 (-2×4)
2×4 = 8:
abs(0) + abs(-5) + 2 (-8)
Since 0 is at the origin, then abs(0) = 0:
abs(-5) - 8×2
Since -5<=0, then abs(-5) = 5:
5 - 8×2
2 (-8) = -16:
-16 + 5
5 - 16 = -11:
Answer: -11
Given that the value of an industrial machine has a decay factor of 0.75 per year, and after six years, it became $7,500 only, this would mean that the original value of the machine would be solved like this: <span>7500 = x(1-.75)^6
</span>7500 = x(0.25)^6
7500 = x(<span>0.00024414062)
7500 = </span><span>0.00024414062x
x = </span><span>30, 720, 000
Hope this answers your question.</span>