From the figure, let the distance of point P from point A on line segment AB be x and let the angle opposite side a be M and the angle opposite side c be N.
Using pythagoras theorem,

and

Angle θ is given by

Given that a = 4 units, b = 5 units, and c = 9 units, thus

To maximixe angle θ, the differentiation of <span>θ with respect to x must be equal to zero.
i.e.

Given that x is a point on line segment AB, this means that x is a positive number less than 5.
Thus

Therefore, The distance from A of point P, so that </span>angle θ is maximum is 0.51 to two decimal places.
Answer:
$-6
Step-by-step explanation:
$(8-14)
= $-6
Hope this helped!
If R is between Q and S then QR+RS=QS
given
QR=x+4
RS=3x-1
and QS=27
x+4+3x-1=27
combine like terms
4x+3=27
minus 3 both sides
4x=24
divide both sides by 4
x=6
sub back
QR=x+4
QR=6+4
QR=10
RS=3x-1
RS=3(6)-1
RS=18-1
RS=17
x=6
QR=10
RS=17