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Mazyrski [523]
3 years ago
9

16) y=1/2sin (30 theta+ 90) + 1

Mathematics
1 answer:
katrin2010 [14]3 years ago
4 0

Answer:

what i need to find there

Step-by-step explanation:

i only find y like an expression

Isolate the variable by dividing each side by factors that don't contain the variable.

y=sin(30t2hea+90)/2+1/16

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Best Answer gets Brainliest!!!<br> PLZ help!
Vika [28.1K]

Answer:

Not proportional

Step-by-step explanation:

If you just Find the unit rate of each thing, you’ll find that none of them are equal to each other.

5 0
3 years ago
Ill give brainliest to the correct answer
Alexxandr [17]

Answer:

7 x 4 = 28

28 x 1/2(dividing by 2) = 14, 14 x 2(two triangles) = 28

4 x 5 = 20(area of square in the middle)

5 x 8 = 40(area of square on one side), 40 x 2 = 80(area of squares on both sides)

Now lets add the given areas:

28 + 20 + 80 = 128 square is your answer.

3 0
3 years ago
Find the value of x
sveticcg [70]

Answer:

<h2>          x = 15</h2>

Step-by-step explanation:

RQ < PR < PQ

TV < UV < UT

ΔPQR~ΔUTV   ⇒     \dfrac{RQ}{TV}=\dfrac{PR}{UV}

\dfrac{8}{x-3}=\dfrac{14}{x+6}\\\\8(x+6)=14(x-3)\\\\8x+48=14x-42\\\\48+42=14x-8x\\\\90=6x\\\\x=90:6=15

6 0
3 years ago
Choose the correct simplification of (4x − 3)(3x2 − 4x − 3).
tester [92]
(4x - 3)(3x^2 - 4x - 3) 

=4x\cdot \:3x^2+4x\left(-4x\right)+4x\left(-3\right)-3\cdot \:3x^2-3\left(-4x\right)-3\left(-3\right) 

=4x\cdot \:3x^2-4x\cdot \:4x-4x\cdot \:3-3\cdot \:3x^2+3\cdot \:4x+3\cdot \:3 

\mathrm{Simplify}\:4x\cdot \:3x^2-4x\cdot \:4x-4x\cdot \:3-3\cdot \:3x^2+3\cdot \:4x+3\cdot \:3:\quad 12x^3-25x^2+9 

=12x^3-25x^2+9
8 0
3 years ago
Solve using long division <br> Please
madreJ [45]

1. Solution,\frac{2x^3+4x^2-5}{x+3}:\quad 2x^2-2x+6-\frac{23}{x+3}

Steps:

\mathrm{Divide}\:\frac{2x^3+4x^2-5}{x+3}:\quad \frac{2x^3+4x^2-5}{x+3}=2x^2+\frac{-2x^2-5}{x+3}

\mathrm{Divide}\:\frac{-2x^2-5}{x+3}:\quad \frac{-2x^2-5}{x+3}=-2x+\frac{6x-5}{x+3}

\mathrm{Divide}\:\frac{6x-5}{x+3}:\quad \frac{6x-5}{x+3}=6+\frac{-23}{x+3}

\mathrm{Simplify}, =2x^2-2x+6-\frac{23}{x+3}

\mathrm{The\:Correct\:Answer\:is\:2x^2-2x+6-\frac{23}{x+3}}

2. Solution, \frac{4x^3-2x^2-3}{2x^2-1}:\quad 2x-1+\frac{2x-4}{2x^2-1}

Steps:

\mathrm{Divide}\:\frac{4x^3-2x^2-3}{2x^2-1}:\quad \frac{4x^3-2x^2-3}{2x^2-1}=2x+\frac{-2x^2+2x-3}{2x^2-1}

\mathrm{Divide}\:\frac{-2x^2+2x-3}{2x^2-1}:\quad \frac{-2x^2+2x-3}{2x^2-1}=-1+\frac{2x-4}{2x^2-1}

\mathrm{The\:Correct\:Answer\:is\:2x-1+\frac{2x-4}{2x^2-1}}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

4 0
3 years ago
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