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seropon [69]
3 years ago
10

The average age of a football player in a league is 27.

Mathematics
1 answer:
KonstantinChe [14]3 years ago
4 0

Answer:

x¯ = 28 years

μ = 27 years

Step-by-step explanation:

Add all the ages and divide the 12 players.

<em>-</em><em> </em><em>Shadow -</em>

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If A = 2.54 and 20B=A what is the value of B?
mixas84 [53]
0.127, 2.54/20 =20*0.127
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3 years ago
Solve 9^x + 4 = 11 for x using the change of base formula log base b of y equals log y over log b.
Sauron [17]

Answer:

If you meant 9^x+4=11, then the answer is approximately 0.866.

If you meant 9^{x+4}=11, then the answer is approximately -2.909 which looks like what you meant based on the choices.

Step-by-step explanation:

9^x+4=11

First step is to get the exponential part by itself. The part that has the variable exponent which is the 9^x term.

To do this we need to subtract 4 on both sides:

9^x=11-4

Simplify:

9^x=7

The equivalent logarithmic form is:

\log_9(7)=x

I always say to myself the logarithm is the exponent that is how I know what to put opposite the side containing the log.

Anyways if you don't have options for computing \log_b(a) in your calculator you need to use the change of base formula.

\frac{\log(7)}{\log(9)}=x

So x \approx 0.8856

I don't see this as a choice so maybe you actually meant the following equation:

9^{x+4}=11

Let's see if this is the correct interpretation.

So the exponential part is already isolated.

So we just need to put in the equivalent logarithmic form:

\log_9(11)=x+4

Now we subtract 4 on both sides:

\log_9(11)-4=x

Again if you don't have the option for computing \log_b(a) in your calculator, you will have to use the change of base formula:

\frac{\log(11)}{\log(9)}-4=x

x \approx -2.909

6 0
3 years ago
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Answer:

3(5 +6) = <em>33</em>

Step-by-step explanation:

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so first you multiply 3 by 5

which is 15

then you multiply 3 by 6

which is 18

and that remains as 15+18

which in total equals <em>33</em>

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Here,

time=4.0s

velocity=39.2m/s

Formula:

a=v/t

=39.2/4.0

=9.8 (ms-2)

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