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3 years ago

What is the equation of a line that contains the points (8, –3) and (–8, 3)?

Mathematics

1 answer:

DerKrebs [107]3 years ago

8 0

Answer:

1. D y = 8

2. C y = −8

Step-by-step explanation:

1.Both points have y-coordinate 8, so the line is horizontal.

A horizontal line has equation y = k

where k is the y-coordinate of all of its points.

The y-coordinate of all points on this line is 8.

Answer: y = 8

2.A line with 0 slope is a horizontal line. All points on a horizontal line have the same y-coordinate.

A horizontal line has equation

y = k

where k is the y-coordinate of all of its points.

The y-coordinate of the given point is -8, so all points must have -8 as the y-coordinate.

Answer: y = -8

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VARVARA [1.3K]

Answer:

okok so the anwser is 1+1

Step-by-step explanation:

1 and add another is 2

boom.

3 0

2 years ago

10t+<img src="https://tex.z-dn.net/?f=%5Cgeq" id="TexFormula1" title="\geq" alt="\geq" align="absmiddle" class="latex-formula">1

Umnica [9.8K]

Answer:

The answer is $t\geq 20$ .

Step-by-step explanation:

To solve the inequality, start by solving for the variable $t$ .

To solve for the variable $t$ , subtract $3.5t$ from both sides. The inequality will look like $6.5t\geq 130$ .

Then, divide both sides by 6.5 in order to get the variable $t$ by itself. The inequality answer will look like $t\geq 20$ .

3 0

2 years ago

Andrew drove 45 more miles than Nicole. If they drove a combined total of 111 miles, how many miles did Nicole drive?

Airida [17]

Answer:

Nicole drove 66 miles.

Step-by-step explanation:

You can set of an equation of 45 - x = 111 x representing the amount of miles Nicole drove. You would subtract 45 from both 45 and 111 and get that x = 66.

8 0

3 years ago

Please help me solve this problem ASAP

DiKsa [7]

$\bold{\huge{\blue{\underline{ Solution }}}}$

<h3>Given :-</h3>

The right angled below is formed by 3 squares A, B and C
The area of square B has an area of 144 inches ²
The area of square C has an of 169 inches ²

We have to find the area of square A?

<h3>Let's Begin :- </h3>

The right angled triangle is formed by 3 squares

We have, 

Area of square B is 144 inches²
Area of square C is 169 inches²

We know that,

$\bold{ Area \: of \: square = Side × Side }$

Let the side of square B be x

Subsitute the required values,

$\sf{ 144 = x × x }$

$\sf{ 144 = x² }$

$\sf{ x = √144}$

$\bold{\red{ x = 12\: inches }}$

Thus, The dimension of square B is 12 inches

Area of square C = 169 inches

Let the side of square C be y

Subsitute the required values,

$\sf{ 169 = y × y }$

$\sf{ 169 = y² }$

$\sf{ y = √169}$

$\bold{\green{ y = 13\: inches }}$

Thus, The dimension of square C is 13 inches.

It is mentioned in the question that, the right angled triangle is formed by 3 squares

The dimensions of square be is x and y

Let the dimensions of square A be z

<h3>Therefore, By using Pythagoras theorem, </h3>

The sum of squares of base and perpendicular height equal to the square of hypotenuse

That is,

$\bold{\pink{ (Perpendicular)² + (Base)² = (Hypotenuse)² }}$

Here, 

Base = x = 12 inches
Perpendicular = z
Hypotenuse = y = 13 inches

Subsitute the required values,

$\sf{ (z)² + (x)² = (y)² }$

$\sf{ (z)² + (12)² = (169)² }$

$\sf{ (z)² + 144 = 169}$

$\sf{ (z)² = 169 - 144 }$

$\sf{ (z)² = 25}$

$\bold{\blue{ z = 5 }}$

Thus, The dimensions of square A is 5 inches

<h3>Therefore,</h3>

Area of square

$\sf{ = Side × Side }$

$\sf{ = 5 × 5 }$

$\bold{\orange{ = 25\: inches }}$

Hence, The area of square A is 25 inches.

6 0

2 years ago

Describe the one basic move you need to change the equation

bixtya [17]

Answer:

Step-by-step explanation: 2x+17=36 ⇒ 2x= -17+36 ⇒ x=8.5+18

so your answer is E

8 0

3 years ago