Step-by-step explanation:
-2.8 +2.4=-.4
-.4+7.8=7.4
7.8-2.8=5
i hope this helps ; )
Answer:
B) 3√2
Step-by-step explanation:
FH = √GH²+FG² = √18 = 3√2
*see attachment for the dot plot being referred to
Answer:
The data is symmetric and shows that he typically sent about 6 to 8 text messages per day
Step-by-step explanation:
The distribution of the data set on a dot plot can be said to be symmetric when most of the data points in the data are located or are concentrated at the center of the dot plot.
As we can observe from the given dot plot in the attachment, it shows that 6 to 8 text messages per day have more frequencies and are just right at the center of the dot plot. This shows the data is symmetric.
This also shows that Reza dents averagely 6 - 8 text messages per day. Reza can be said to have typically sent 6 - 8 text messages per day.
The rest statements about the dot plot are untrue.
First, you want to find out how many kilometers are in one mile. So you take the information you are given and divide 16 km by 10 and you get 1.6 km/1mi. Now, you know that the distance between the two towns is 45 miles, so simply multiply 1.6 by 45 to get 67.5 km in 45 mi.
9514 1404 393
Answer:
138.77
Step-by-step explanation:
Your scientific or graphing calculator will have exponential functions for bases 10 and e. On the calculator shown in the first attachment, they are shifted (2nd) functions on the log and ln keys. Consult your calculator manual for the use of these functions.
The value can be found using Desmos, the Go.ogle calculator, or any spreadsheet by typing 10^2.1423 as input. (In a spreadsheet, that will need to be =10^2.1423.) The result using the Go.ogle calculator is shown in the second attachment.
You can also use the y^x key or the ^ key (shown to the left of the log key in the first attachment). Again, you would calculate 10^2.1423.
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We have assumed your log is to the base 10. If it is base e (a natural logarithm), then you use the e^x key instead. Desmos, and most spreadsheets, will make use of the EXP( ) function for the purpose of computing e^( ). You can type e^2.1423 into the Go.ogle calculator.
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<em>Additional comment</em>
There are also printed logarithm tables available that you can use to look up the number whose log is 0.1423. You may have to do some interpolation of table values. You should get a value of 1.3877 as the antilog. The characteristic of 2 tells you this value is multiplied by 10^2 = 100 to get the final antilog value.
The logarithm 2.1423 has a "characteristic" (integer part) of 2, and a "mantissa" (fractional part) of 0.1423.