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Ksenya-84 [330]
4 years ago
6

If the arc length of a sector in the unit circle is 4.2, what is the measure of the angle of the sector?

Mathematics
2 answers:
Dennis_Churaev [7]4 years ago
7 0
The unit circle is a circle with radius r=1, so you have

L=r\theta\implies4.2=\theta

where \theta is measured in radians, so \theta\approx241^\circ.
solniwko [45]4 years ago
5 0

Answer:  4.2 radian or  241^{\circ}

Step-by-step explanation:

Let \theta represents the measure of the angle of the sector.

We know that in a unit circle , the radius = 1 unit

The formula to calculate the length of arc of sector is given by :-

L=r\theta

Then , the measure of the angle of the sector is given by :-

\theta=\dfrac{L}{r}\\\\\Rightarrow\ \theta=\dfrac{4.2}{1}=4.2\text{ radian}

In degrees , the measure of the angle of the sector will be :-

4.2\times\dfrac{180^{\circ}}{\pi}=240.642273955\approx241^{\circ}

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sammy [17]

By applying the definition of product between two <em>square</em> matrices, we find that \vec A \,\cdot \,\vec A = \left[\begin{array}{cc}1&2\\3&6\end{array}\right] \cdot \left[\begin{array}{cc}1&2\\3&6\end{array}\right] is equal to the matrix \vec A \,\cdot \,\vec A = \left[\begin{array}{cc}7&14\\21&42\end{array}\right]. (Correct choice: D)

<h3>What is the product of two square matrices</h3>

In this question we must use the definition of product between two <em>square</em> matrices to determine the resulting construction:

\vec A \,\cdot \,\vec A = \left[\begin{array}{cc}1&2\\3&6\end{array}\right] \cdot \left[\begin{array}{cc}1&2\\3&6\end{array}\right]

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By applying the definition of product between two <em>square</em> matrices, we find that \vec A \,\cdot \,\vec A = \left[\begin{array}{cc}1&2\\3&6\end{array}\right] \cdot \left[\begin{array}{cc}1&2\\3&6\end{array}\right] is equal to the matrix \vec A \,\cdot \,\vec A = \left[\begin{array}{cc}7&14\\21&42\end{array}\right].

To learn more on matrices: brainly.com/question/11367104

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