Question

If you are given the graph of h(x) = log. x, how could you graph m(x) = log2(x+3)?

Answer 1

Answer:

Option (d).

Step-by-step explanation:

Note: The base of log is missing in h(x).

Consider the given functions are

$h(x)=\log_2x$

$m(x)=\log_2(x+3)$

The function m(x) can be written as

$m(x)=h(x+3)$           ...(1)

The translation is defined as

$m(x)=h(x+a)+b$           .... (2)

Where, a is horizontal shift and b is vertical shift.

If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.

If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.

On comparing (1) and (2), we get

$a=3,b=0$

Therefore, we have to translate each point of the graph of h(x) 3 units left to get the graph of m(x).

Hence, option (d) is correct.