Question

Yulet rolls 2 fair dice and adds the results from each. Work out the probability of getting a total less than 7.

Answer 1

Probability of getting a total less than 7 is  $\frac{5}{12}$.

Step-by-step explanation:

Given,

2 dice are thrown.

To find the probability of getting a total less than 7.

Formula

P(an event) = number of required outcomes ÷ total possible outcomes

Now,

When 2 dice are thrown, possible outcomes are:

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6) = 36 times

Getting a total less than 7 are : (1,1), (1,2), (1,3), (1,4), (1,5), (2,1), (2,2), (2,3), (2,4),(3,1), (3,2), (3,3),(4,1), (4,2),(5,1) = 15 times

Hence,

Probability of getting a total less than 7 = $\frac{15}{36}$ = $\frac{5}{12}$