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Neporo4naja [7]

4 years ago

6

The results of pass-fail exams in math and physics given to 200 students are displayed in the cross-table. Pass Physics Fail Phy

sics Total Pass Math 45 65 110 Fail Math 35 55 90 Total 80 120 200 What percentage of students failed math but passed physics? What percentage of students failed physics and passed math?

1 answer:

Tju [1.3M]4 years ago

5 0

Answer:

Step-by-step explanation:

I can help

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A person that weighs 179 lbs needs an IV Drip in mL. The drug only comes in powder form but can be converted as 10 mg is equal t

OleMash [197]

Solution:

Weight of person = 179 lbs

As given person needs IV Drip in m L.

Also,→ 10 mg = 2 m L

Now, you must remember , → 1 lbs = 0.453 Kg (approx)

→179 lbs = 179 × 0.453 Kg = 78.47 Kg (approx)

The person needs at least 60 mg for each Kg they weigh.

⇒ 1 Kg → 60 mg

⇒ 78.47 × 1 Kg → 78.47 × 60 mg

⇒ 78.47 Kg → 4708.2 mg

Also, 10 mg → 2 m L

⇒ 1 mg → $\frac{1}{5}$ m L

⇒ 4708 . 2 mg → $\frac{1}{5} \times 4708.2$ m L

⇒ 4708 . 2 mg → 941. 64 ml

8 0

3 years ago

30 POINTS If you help.....

Flauer [41]

Answer:

$0.075$

Step-by-step explanation:

<u>Step 1: Make the denominator a whole number</u>

<u /> $\frac {0.48}{6.4}$

$\frac {0.48*5}{6.4*5}$

$\frac{2.4}{32}$

<u>Step 2: Divide</u>

<u /> $\frac{2.4}{32}$

$0.075$

Answer: $0.075$

4 0

4 years ago

Trapezoid TRAP was dilated by a scale factor of one half to create trapezoid T'R'A'P'.

alexira [117]

Answer:

Point X

Step-by-step explanation:

If you look, you can see that X is the center point for both TRAP and T'R'A'P'. I also just took the test myself and got it correct.

Hope this helps!

6 0

3 years ago

Read 2 more answers

It costs $3.24 for a pack of 18 pencils.

max2010maxim [7]

The answer is 2.09

Step-by-step explanation:

7 0

3 years ago

We are conducting a hypothesis test to determine if fewer than 80% of ST 311 Hybrid students complete all modules before class.

Juli2301 [7.4K]

Answer:

$z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124$

Null hypothesis: $p\geq 0.8$

Alternative hypothesis: $p < 0.8$

Since is a left tailed test the p value would be:

$p_v =P(Z$

So the p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis: $p\leq 0.8$

Alternative hypothesis: $p > 0.8$

$p_v =P(Z>2.124)=0.013$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation

n=110 represent the random sample taken

X=97 represent the students who completed the modules before class

$\hat p=\frac{97}{110}=0.882$ estimated proportion of students who completed the modules before class

$p_o=0.8$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v{/tex} represent the p value (variable of interest) 2) Concepts and formulas to use We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.8 or 80%: Null hypothesis:[tex]p\geq 0.8$

Alternative hypothesis: $p < 0.8$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(Z$

So the p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis: $p\leq 0.8$

Alternative hypothesis: $p > 0.8$

$p_v =P(Z>2.124)=0.013$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

5 0

4 years ago