Question

A 0.17 kg hockey puck slows down trom 54 m/s to 35 m/s when it slides on horizontal ice surface. Find the change in momentum of the puck?

Answer 1

Answer:

D_momentum = 3.23[kg*m/s]

Explanation:

The change of moment can be easily determined by applying the principle of momentum and amount of movement

initial data are:

$m_{1}=0.17[kg]\\ m_{2}=0.17[kg]\\v_{1}=54[m/s]\\v_{2}=35[m/s]\\D_{momentum}= m_{1}*v_{1}-m_{2}*v_{2}\\D_{momentum}=0.17(54-35)\\D_{momentum}= 3.23[kg*m/s]$