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3 years ago

Pls help will crown you

Mathematics

2 answers:

Rzqust [24]3 years ago

5 0

Answer:75

Step-by-step explanation:

Ksenya-84 [330]3 years ago

4 0

Answer: 69.5

Step-by-step explanation:

You’d use Pythagorean’s there I’m which is a^2+b^2=c^2

Then you’d plug in your values.....

1. 60^2+35^2=c^2

2. 3600+1225=c^2

3. 4825=c^2

4. Then to solve for c you square root both sides and round to the tenth

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Part B

EastWind [94]

Answer:

Step-by-step explanation:

the slope of line n is also -3 as it is parallel to m

The answer is A

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3 years ago

Find the perimeter of the shape

dezoksy [38]

Answer:

29.71

Step-by-step explanation:

8+6+5pi

14+15.71

29.71

15.71 is approx 5pi

6 0

2 years ago

FIRST PERSON TO ANSWER GETS BRAINIEST ANSWER SO HURRY QUICK QUICK FIRST PERSON TO ANSWER GETS BRAINIEST ANSWER SO HURRY QUICK QU

Zielflug [23.3K]

1.92 cm = 15 cm
1.2 cm = ? cm

$\frac{15}{1.92} = \frac{?}{1.2}$

15*1.2 = 1.92*?
18 = 1.92*?
9.375 = ?

The answer is B

3 0

2 years ago

Please help me!!! will mark brainlest

Licemer1 [7]

A. To be able to have the 2 sides ( the 2 triangles) line up correctly, Net A would be the correct one.

B. AB = 3

BC = 5

CD = 9.4

C. Surface area:

9.4 x 5 = 47

9.4 x 3 = 28.2

9.4 x 4 = 37.6

3 x 4 = 12

Total: 47 + 28.2 + 37.6 + 12 = 124.8 sq. in.

8 0

3 years ago

From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s

Mnenie [13.5K]

<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

60 out of 100 scores are passing scores, hence $n = 100, \pi = \frac{60}{100} = 0.6$

95% confidence level

So $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7$

The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

A similar problem is given at brainly.com/question/16807970

5 0

2 years ago