All categories

3 years ago

What is the probability that a marble chosen at random is

Mathematics

2 answers:

Rufina [12.5K]3 years ago

5 0

Answer:

6/11

Step-by-step explanation:

Ed2020

Brums [2.3K]3 years ago

4 0

Answer:

$P=\frac{6}{11}$

Step-by-step explanation:

The probability can be defined as the ratio between the possible events and the total number of outcomes.

In this case, according to the image attached, the total number of outcomes is 11, because they are 11 marbles in total.

Now, the specific event is all shaded marbles or labeled with a multiple of 3. With this specific characteristics 6 marbles, because there are 5 shaded marbles and 6 is a multiple of 3. So, the possible events are 6.

Therefore, the probability is

$P=\frac{6}{11}$

The right answer is the last choice.

You might be interested in

Given limit of f (x) = 4 as x approaches 0. what is limit of one-fourth left-bracket f (x) right-bracket superscript 4 baseline

Otrada [13]

The limit of the given function if $\lim_{x \to 0} f(x)=4$ is 64

<h3>Limit of a function</h3>

Given the following limit of a function expressed as;

$\lim_{x \to 0} f(x)=4$

We are to determine the value of the function

$\frac{1}{4} \lim_{x \to 0} [f(x)]^4$

This can also be expressed as

$\frac{1}{4} \lim_{x \to 0} [f(x)]^4\\ = \frac{1}{4}(4)^4 \\=1/4\times 256\\=64$

Hence the limit of the given function if $\lim_{x \to 0} f(x)=4$ is 64

Learn more on limit of a function here: brainly.com/question/23935467

#SPJ1

4 0

2 years ago

Need help ASAP

Westkost [7]

Answer:

1.333 repeated

Step-by-step explanation:

8 0

2 years ago

Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).

Oduvanchick [21]

For two complex numbers $z_1=re^{i\theta}=r(\cos\theta+i\sin\theta)$ and $z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi)$ , the product is

$z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))$

That is, you multiply the moduli and add the arguments. You have $z_1=7e^{i40^\circ}$ and $z_2=6e^{i145^\circ}$ , so the product is

$z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}$

3 0

3 years ago

Read 2 more answers

Please help asap i am timed will give brainliest

wariber [46]

Answer

Step-by-step explanation:

4 0

3 years ago

Given the function f(x) = 2^x, find the value of f^−1(32).

klio [65]

$f(x)= 2^{x}$

We are to find the value of $f^{-1}(32)$

First we need to find the inverse of f(x) . The inverse of $2^{x}$ is $\frac{ln(x)}{ln(2)}$ .

Steps to find inverse of f(x) are shown below in the image.

So $f^{-1}(32)$ = $\frac{ln(32)}{ln(2)}=5$

Therefore, the correct answer is option C

5 0

3 years ago