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Gekata [30.6K]
3 years ago
10

Marnie packed 18 boxes in 3 hours, which was 72% of the total number of boxes she had to pack. How many boxes did Marnie have to

pack? 13 25 54 216
Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
5 0
25 just do the math its simple
Rama09 [41]3 years ago
3 0

Answer:

Your answer is 25

Step-by-step explanation: Just divided 18 by 72% and you 25. Hope this helps. Made simple not complicated.


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What is the solution set for 6x-(3x+4)=x-40
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First, open the parentheses (make sure you distribute the '-':

6x - 3x - 4 = x - 40
3x - 4 = x - 40
2x = -36
x = -18

The solution set is {-18}
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3 years ago
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Answers should be exact decimals (please do not leave as fractions or unfinished calculations). A six-sided die (cube) with face
Ghella [55]

Answer:

(a) P = 0.0001

(b) P = 0.6561

(c) P = 0.2916

(d) P = 0.3439

(e) P = 0.2

Step-by-step explanation:

This is a probability problem.

The dice is rolled 4 times (n=4) and we calculate the probability of different outcomes.

The probability of a 6 in a roll is 0.5.

The probability of a 1, 2, 3, 4 or 5 in a roll is 0.5/5=0.1.

<u />

<u>a) Outcome: all the rolls are 2.</u>

The probability of having a 2 in a roll is 0.1, so we can calculate the probability of having a 2 in four consecutive rolls as

P(x1=2;x2=2;x3=2;x4=2)=P(x=2)^4=0.1^4=0.0001

<u>b) Outcome: none of the rolls is a 2.</u>

The probability of having any other number but 2 in 4 rolls is:

P(x1\neq2;x2\neq2;x3\neq2;x4\neq2)=P(x\neq2)^4=(1-0.1)^4=0.6561

<u>c) Outcome: exactly one roll is a 2</u>

This is the sum of the probability of having a 2 in the first, second, third or fouth roll, and others numbers in the rest of the rolls. These 4 combinations have the same probability, so we will multiply it by 4.

P(exactly \,one\,2)=4*P(x1=2;x2\neq2;x3\neq2;x4\neq2)\\\\P(exactly \,one\,2)=4*0.1*0.9*0.9*0.9=0.2916

<u>d) Outcome: at least one of the rolls is a 2</u>

In this case, is the probability of having at least one 2, is the sum of the probability of getting a 2 in the first roll, the probability of getting a 2 in the second roll, the probability of getting a 2 in the third roll and the probability of getting a 2 in the four roll:

P(x1=2)+P(x2=2)+P(x3=2)+P(x4=2)=0.1+0.9*0.1+0.9*0.9*0.1+0.9*0.9*0.9*0.1\\\\P(x1=2)+P(x2=2)+P(x3=2)+P(x4=2)=0.1+0.09+0.081+0.0729\\\\P(x1=2)+P(x2=2)+P(x3=2)+P(x4=2)=0.3439

<u>e) Outcome: either the first roll or the last roll is a 2</u>

The probability of getting a 2 in the first roll is equal to having it in a fourth roll, and its the probability of getting a 2 in a roll (multiplied by 2, beacuse there can be either in the first or in the last roll).

P(x1=2)+P(x4=2)=2*P(x=2)=2*0.1=0.2

6 0
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ILL GIVE YOU THE BRAINLEST IF YOU ANSWER MY QUESTION CORRECTLY
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Answer:

Is this correct?

Step-by-step explanation:

idk

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Answer:

Step-by-step explanation:

The discriminant comes from the quadratic formula. We use the discriminant to determine, before factoring, what types of solutions we can expect when we do factor. In the quadratic formula, the discriminant is under a square root sign. If the number under a square root sign is negative (meaning the discriminant is negative), we will not have real number solutions because you can't have a negative number under a square root. So a is your choice.

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