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4 years ago

Find the quartiles for these data values of 5, 7, 7, 8, 10, 11, 12, 15, 17

Mathematics

1 answer:

Kazeer [188]4 years ago

8 0

The median {Q2} is 10

Q1 is 7+7/2 which is 7

Q3 is 15+12/2 which is 13.5

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CosX sec^2X tanX - cosX tan^3X = sinX

ch4aika [34]

$\cos x\sec^2x\tan x-\cos x\tan^3x=\cos x\tan x\left(\sec^2x-\tan^2x\right)=\sin x\left(\sec^2x-(\sec^2x-1)\right)=\sin x$

4 0

3 years ago

A fish processing company in Charlotteville processes three types of products: Type A, Type B and Type C. Its operations involve

Neporo4naja [7]

Answer:

A fish processing company in Charlotteville processes three types of products: Type A, Type B, and Type C. Its operations involve three basic activities: cleaning, cutting and packaging.

Step-by-step explanation:

8 0

3 years ago

I need help now I’m stuck!

trapecia [35]

Whats the question?

6 0

3 years ago

Read 2 more answers

You want Brainliest help me plsss

yKpoI14uk [10]

Answer:

the slope in the equation is 5, while the slope on the graph is 2

3 0

3 years ago

Assume the world catch of fish in 1950 was 12 million tons and in 1955 it was 96 million tons.

Rama09 [41]

The rate of change is 16.8 million tons per year

Solution:

Given that, the world catch of fish in 1950 was 12 million tons and in 1955 it was 96 million tons

The average rate of change is given by formula:

$\text{ Average rate of change } = \frac{\text{ change in value }}{\text{ number of years }}$

Value in 1950 = 12 million tons

Value in 1955 = 96 million tons

Change in value = value in 1955 - value in 1950

Change in value = 96 million - 12 million = 84 million tons

Number of years = 1950 to 1955 = 5 years

Substitute the given values in formula,

$\text{ Average rate of change } = \frac{84 \text{ million tons}}{5} = 16.8 \text{ million tons}$

Thus rate of change is 16.8 million tons per year

5 0

3 years ago