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Nastasia [14]
3 years ago
10

Question 14

Mathematics
1 answer:
Reil [10]3 years ago
6 0

Answer:

The system of equations has a one unique solution

Step-by-step explanation:

To quickly determine the number of solutions of a linear system of equations, we need to express each of the equations in slope-intercept form, so we can compare their slopes, and decide:

1) if they intersect at a unique point (when the slopes are different) thus giving a one solution, or

2) if the slopes have the exact  same value giving parallel lines (with no intersections, and the y-intercept is different so there is no solution), or

3) if there is an infinite number of solutions (both lines are exactly the same, that is same slope and same y-intercept)

So we write them in slope -intercept form:

First equation:

6x+y=-1\\y=-6x-1

second equation:

-6x-4y=4\\-6x=4y+4\\-6x-4=4y\\y=-\frac{3}{2} x-1

So we see that their slopes are different (for the first one slope = -6, and for the second one slope= -3/2) and then the lines must intercept in a one unique point. Therefore the system of equations has a one unique solution.

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Can someone please help? Only answer the question correctly, please!<br><br> Question is down below.
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Answer:

<h2>{6y}^{2}</h2>

Step-by-step explanation:

<em><u>Given</u></em><em><u>, </u></em>

\frac{1}{ {6y}^{ - 2}  }

<em><u>Since</u></em><em><u>,</u></em>

{x}^{ab}  =  {( {x}^{a} )}^{b}

<em><u>Hence</u></em><em><u>,</u></em>

=  \frac{1}{ {( {6y}^{2} )}^{ - 1} }

<em><u>Since</u></em><em><u>,</u></em>

\frac{1}{ {x}^{ - 1} }  = x

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=  {6y}^{2} (ans)

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