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2 years ago

Which of the points given divide the line segment AB in the ratio 2:3?

Mathematics

1 answer:

alexira [117]2 years ago

4 0

Answer: The correct answer is Choice D, (5, 7).

First, we need to identify the slope from A to B.
It will be -5/-5. In other words, to go from A to B, we move down 5 spaces and left 5 spaces.

If we are going to divide the segment, we are not going to move all 5 spaces in each direction.

Since we are looking for a 2:3 ratio, we are only moving 2 out of the total of 5 spaces. It is 2 over 5, because 2 + 3 makes a total of 5.

Therefore, we only move down 2 and left 2 spaces from Point A. That will put us at the point (5, 7).

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Point O is on line segment \overline{NP} NP . Given OP=8OP=8 and NO=2,NO=2, determine the length \overline{NP}. NP

timama [110]

Answer: The length of $\overline{NP}$ is 10 units.

Step-by-step explanation:

We are given that,

Point <em>O</em> is on line segment $\overline{NP}$ .

Then, $\overline{NP}=\overline{NO}+\overline{OP}$ (i)

Since we have given that OP=8 units and NO=2 units .

Now we will substitute these values in (i), we will get

$\overline{NP}=8\ units+2\ units\\\\\Rightarrow\ \overline{NP}=10\ units$

Hence, the length of $\overline{NP}$ is 10 units.

4 0

3 years ago

0.5,3/16,0.755/49 least to greatest

SVEN [57.7K]

0.5 is least greatest

7 0

3 years ago

Read 2 more answers

Proper

vlabodo [156]

Answer:

QR(3), RS(3), PQ(3), ST(11), RP(6), RT(14), SP(9), QT(17)

Step-by-step explanation:

The diagram is not shown, but we assume the points are in the sequence ...

P, Q, R, S, T

Since QR = RS, R is apparently the midpoint of QS, So ...

23. QR = 6/2 = 3

24. RS = QR = 3

25. PQ = QR = 3

26. ST = PT -PQ -QS = 20 -3 -6 = 11

27. RP = PQ +QR = 3 +3 = 6

28. RT = RS +ST = 3 +11 = 14

29. SP = PQ +QS = 3 +6 = 9

30. QT = QS +ST = 6 +11 = 17

6 0

3 years ago

Fran bought 4 shirts that were each $13 each. She also bought a pair of socks for 4.29. What was the total amount Fran pair for

agasfer [191]

4x13=52 52+4.29=56.29

8 0

3 years ago

The South Coast Air Basin (Los Angeles, Orange, and San Bernardino counties) does not meet the air quality standards for carbon

Archy [21]

Answer:

0.2225 gr/mile

Step-by-step explanation:

Let's work out first the amount of CO sent out in 1990.

The population we estimated in 12.5 million people with a total of driven miles per year of about

12.5 million*8,700 = 108,750 million miles.

With an CO emission factor of 0.9 g per mile, we would have a total of CO emitted rounding 0.9*180,750 = 97,875 million grams

Now, we must estimate the population for 2020.

Since we are assuming an exponential growth, the population in year t is given by a function

$\bf P(t)= Ce^{kt}$

where C and k are constants to be determined.

We can take 1980 as year 0. This way calculations are lighter. 1990 is year 10 and 2020 is year 20.

So P(0) = 10.3 and C=10.3

So far we have

$\bf P(t)= 10.3e^{kt}$

Given that P(10)=12.5

$\bf 10.3e^{k*10}=12.5\rightarrow e^{10k}=\frac{12.5}{10.3}=1.21359\rightarrow \\10k=log(1.21359)\rightarrow k=0.01936$

And the function that models the population growth is

$\bf P(t)= 10.3e^{0.01936t}$

We need P(20)

$\bf P(20)= 10.3e^{0.01936*20}=10.3e^{0.38717}=15.17\;million$

If the miles driven per person per year remains constant at 8700 mi/yr.person, then we have a total miles driven of

15.17*8,700=131,979 million miles, so the CO emitted would be 0.9*131,979=118,781.1 million grams.

The 30% of the CO sent out in 1990 is 0.3*97,875=29,362.5 million grams.

We must reduce 118,781.1 down to 29,362.5

Hence the new CO emission factor would be

29,362.5/131,979 = 0.2225 gr/mile

6 0

3 years ago