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Aliun [14]
3 years ago
14

Solve 14x + 10 > 9x+ 15.

Mathematics
1 answer:
ddd [48]3 years ago
7 0

Answer:

Step-by-step explanation:

14x + 10 > 9x+ 15

subtract 9x from both sides,

14x -9x + 10 > 9x -9x +15

5x + 10 > 15

subtract 10 from both the sides,

5x + 10 -10 > 15 -10

5x > 5

divide by 5

5x/5 > 5/5

x > 5

Value of x = { 6,7,8,..........}

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TrianglesABC and DEF are <br> Similar<br> Not similar
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2 years ago
Write the standard form of the line that passes through (-1,-3) and (2,1).
kobusy [5.1K]

Answer:

Step-by-step explanation:

\mathrm{Line\:passing\:through\:}\left(-1,\:-3\right)\mathrm{,\:}\left(2,\:1\right)\\\\\mathrm{Find\:the\:line\:}\\\mathbf{y=mx+b}\mathrm{\:passing\:through\:}\left(-1,\:-3\right)\mathrm{,\:}\left(2,\:1\right)\\\\\mathrm{Compute\:the\:slope\:}\left(-1,\:-3\right),\:\left(2,\:1\right):\quad \\m=\frac{4}{3}\\\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\\\\\left(x_1,\:y_1\right)=\left(-1,\:-3\right),\:\left(x_2,\:y_2\right)\\\left\\

\\m=\frac{1-\left(-3\right)}{2-\left(-1\right)}\\\\Refine\\\\m=\frac{4}{3}\\\\\mathrm{Compute\:the\:}y\mathrm{\:intercept}:\quad b=-\frac{5}{3}\\\\y=\frac{4}{3}x-\frac{5}{3}\\

Convert equation to standard form

y - \frac{4}{3} x + \frac{5}{3} = 0\\\\Multiply \:through\: by\: 3;\\\\3\times (y - \frac{4}{3} x + \frac{5}{3} )=0\\\\3y -4x+5 = 0\\Arrange\:n\:form\:of \:;\\Ax +By = C\\\\-4x +3y =-5

5 0
3 years ago
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