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3 years ago

9

What method would you choose to solve the equation 2x2 – 7 = 9? Explain why you chose this method.

2 answers:

Illusion [34]3 years ago

7 0

Normal solution;
By taking -7 to the RHS, you will have
$2 x^{2} =16$
dividing both sides by 2 gives;
$x^{2} =8
x= \sqrt{8} 
x=2 \sqrt{2}$

Kisachek [45]3 years ago

5 0

<span>This is a quadratic equation . We order to equate to zero

</span>2x²<span> – 7 = 9
</span>
2x² - 7-9 = 0
2x² - 16 = 0

This equation is a binomial
2* (x² - 8) = 0
<span>We choose the simplest method . The equation with practice it can be calculated in the memory
</span><span>
The product is equal to 0 if one of the factors is zero
</span>
2≠0 ∨ x² - 8 = 0
x² = √8
x = √8 ∨ x= - √8

Answer : x = √8 ∨ x = -√8

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Answer:

Option D.(60, 135)

Step-by-step explanation:

Let

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y ----> the number of acres of carrots

we know that

The inequality that represent the problem is equal to

$x+y\leq 200$

so

<em>Verify each case</em>

case A) (-50,160)

substitute the value of x and the value of y in the inequality and then compare the result

$-50+160\leq 200$

$110\leq 200$ ----> is true

The point is a solution for the inequality, but is not a viable solution because the number of acres can not be a negative number

case B) (80,160)

substitute the value of x and the value of y in the inequality and then compare the result

$80+160\leq 200$

$240\leq 200$ ----> is not true

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case C) (75,-200)

substitute the value of x and the value of y in the inequality and then compare the result

$75-200\leq 200$

$-125\leq 200$ ----> is true

The point is a solution for the inequality, but is not a viable solution because the number of acres can not be a negative number

case D) (60,135)

substitute the value of x and the value of y in the inequality and then compare the result

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The variance of a distribution is the square of the standard deviation

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<h3>How to calculate the variance</h3>

Start by calculating the expected value using:

$E(x) = \sum x* P(x)$

So, we have:

$E(x) = 1 * 0.3 + 2* 0.2 +3 * 0.2 + 4 * 0.1 + 5 * 0.2$

This gives

$E(x) = 2.7$

Next, calculate E(x^2) using:

$E(x^2) = \sum x^2* P(x)$

So, we have:

$E(x^2) = 1^2 * 0.3 + 2^2* 0.2 +3^2 * 0.2 + 4^2 * 0.1 + 5^2 * 0.2$

$E(x^2) = 9.5$

The variance is then calculated as:

$Var(x) = E(x^2) - (E(x))^2$

So, we have:

$Var(x) = 9.5 - 2.7^2$

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Approximate

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Read more about variance at:

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