2 years ago

The hypotenuse of a 45-45-90 triangle measures 10√5 in.

Mathematics

2 answers:

dezoksy [38]2 years ago

6 0

This is the equation all worked out with the trick to 45 45 90 triangles to the side.

the answer is B

Naddik [55]2 years ago

3 0

Let x be the length of one leg ⇒
<span>By the Pythagorean theorem:</span>

x² + x² = (10√5)²
2x² = 500
x² = 500/2
x² = 250
x = √250 = 5√10

You might be interested in

Larry wants to enlarge a cube with edges of 3cm so that it's volume will be 8 times larger. How long must each edge of the enlar

Monica [59]

The answer is 6 inches, 3*3*3 equals 27, the current volume of the cube, 27*8 equals 216, the new volume, 6*6*6 equals 216, so the side lengths equal 6 inches.

6 0

3 years ago

The ratio of black bags to blue bags is 5 to 3. If there are a total of 40 bags,

Simora [160]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What are the zeros of f(x)=(x+5)(x-9)?

klemol [59]

Answer:

x= -5

x= 9

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

For the vectors u = ⟨2, 9⟩, v = ⟨4, –8⟩, and w = ⟨–12, 4⟩, what is u + v + w? ⟨6, 1⟩ ⟨6, 5⟩ ⟨-6, 5⟩ ⟨-6, 21⟩

Levart [38]

Answer:

< - 6, 5 >

Step-by-step explanation:

Add the corresponding components of each vector, that is

u + v + w

= < 2, 9 > + < 4, - 8 > + < - 12, 4 >

= > 2 + 4 - 12, 9 - 8 + 4 >

= < - 6, 5 >

6 0

2 years ago

Read 2 more answers

A rectangular field with perimeter of 80m is to have an area of at least 380m² . Describe the possible lengths and of the field.

Kryger [21]

$let \: x \: be \: the \: length \\ let \: y \: be \: the \: width$

$perimeter = 2x + 2y \\ area = xy$

$2x + 2y = 80 \\ xy = 380 \\ \\ x + y = 40 \\ xy = 380 \\ \\ x = 40 - y \\ (40 - y)y = 380$

$40y - y {}^{2} = 380 \\ y {}^{2} - 40y + 380 = 0 \\ y {}^{2} - 40y + 400 = 20 \\ (y - 20) {}^{2} = 20 \\ y - 20 =± \sqrt{20} \\ y_{1}=20-√20≈15.52786\\ y_{2}=20+√20≈24.4721$

6 0

2 years ago