Answer:
A. Plane B because it was 9.33 miles away
B. 48 units
Step-by-step explanation:
A. Since the airplanes fly at an angle to the runway, their direction forms a triangle with the runway with their height above the ground as the opposite of the angle and their distance from the airport as the hypotenuse.
So for airplane A with 44° angle of departure,
sin44° = y/h where y = height above the ground and h = distance from airport
So h = y/sin44° = 6/sin44° = 8.64 miles
So for airplane B with 40° angle of departure,
sin40° = y/H where y = height above the ground and H = distance from airport
So H = y/sin40° = 6/sin40° = 9.33 miles
Since airplane B is at 9.33 miles away from the airport whereas airplane A is 8.64 miles from the airport, airplane B is farther away.
B. We know that scale factor = new size/original size
Our scale factor = 4 and original size = 12 units. So,
new size = scale factor original size = 4 × 12 = 48 units.
Answer:
(0,1)
Step-by-step explanation:
The mid point of A(-2,2) and B(2,-4) is the coordinates of point P, which is (x,y)
Hence, the line AB = AP + PB.
At point AP: x = (-2+2)/2 = 0
also, point PB: y = (2 - 4)/2 = -1
Therefore, coordinates of point P = (0,-1)
To rearrange you must first simplify
aq-ac=d
add ac to each side:
aq=d+ac
then divide by a:
q=(d/a)+c and this is your answer
Answer: Fish A: 9 inches ; Fish B: 6 inches
Step-by-step explanation:
This can be turned into a systems of equation, where x equals the length of fish A and y equals the length of fish B:
3x + 2y = 39 → -3x - 2y = -39
3x + 4y = 51 → 3x +4y = 51
Combine: 0 + 2y = 12 → y = 6 inches.
Plug back in: 3x + 2(6) = 39 → 3x = 27 → x = 9 inches.
