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creativ13 [48]
3 years ago
11

HELP!!! all work is due in 2 hours

Mathematics
1 answer:
Assoli18 [71]3 years ago
8 0
The outside arcs for a circle enveloping a triangle will always equal 360.

Set up an equation that has all arcs equal 360:

(3x + 30) + (5x + 10) + (2x + 20) = 360

Combine like terms:

3x + 5x + 2x = 10x
30 + 10 + 20 = 60

10x + 60 = 360

Subtract 60 from both sides:

10x = 300

Divide both sides by 10 to get x by itself:

x = 30

We can now find the values of the arcs:

3(30) + 30 = 90 + 30 = 120
5(30) + 10 = 150 + 10 = 160
2(30) + 20 = 60 + 20 = 80

All three arc lengths are different, which means that the triangle's side lengths are all different. This makes the triangle a scalene triangle.
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NGC is a hot air balloon in the sky from her spot on the ground. The angle of elevation from Angie to the balloon is 40°. If she
Goshia [24]

Answer:

The distance from hot air balloon to the ground  AC=50.1457 ft.

Step-by-step explanation:

Labelled diagram of given scenario is shown below.

Given that,

An angle of elevation of Hot air balloon by Angie is 40°.

When she  stepped back 200 ft then angle of elevation was 10°.

Height of Angie is  5.5 ft.

To find: How far off the ground is a hot air balloon.

So, from figure

Height of Angie (BC) = 5.5ft

  In triangle ΔABD,

         ⇒                    tan {40\si {\degree}} = \frac{AB}{BD}

         ⇒                      AB = tan (40) \times BD          ....................(1)

Now, In triangle ΔABE

         ⇒                  tan (10)= \frac{AB}{200+BD}

         ⇒                 AB = tan(10)\times (200+BD)

Here, substituting the value AB from Equation (1) we get,

                        tan(10)\times (200+BD)= tan(40)\times BD

                      tan(10)\times 200+tan(10)\times BD= tan(40)\times BD

        ⇒         BD\times (tan(40)-tan(10))=tan(10)\times 20        

        ⇒                   BD\times 0.6628 = 35.2654

        ⇒                       BD = \frac{35.2654}{0.6628} =53.2067 ft        

Now, finding the value of AB from equation (1)

                                 AB= tan(40)\times 53.2067=0.8391\times 53.2067

                                 AB=44.6457 ft              

Therefore Length of AC= AB+BC = (44.6457 + 5.5) ft

                                  AC=50.1457 ft.

Hence,

The distance from hot air balloon to the ground  AC=50.1457 ft.                

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What is the slope of a line that is parallel to the line y=3/4x+2
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If two lines are parallel to one another, then their slopes are identical.  The slope in the line above is 3/4.  Therefore, a line parallel to that line will also have a slope of 3/4, it will just have a different y-intercept.
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1 and 2

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