All categories

2 years ago

If 3x−4y=2 is a true equation, what would be the value of -4(3x-4y)

Mathematics

1 answer:

Naddika [18.5K]2 years ago

3 0

Answer:

-8

Step-by-step explanation:

If 3x-4y=2, then for any number a we also have a(3x-4y)=a(2) by multiplication property of equality.

Therefore, for a=-4 we have -4(3x-4y)=-4(2) which means the value of -4(3x-4y) is -8.

You might be interested in

Please help me with this

jekas [21]

Answer:

The length= 16cm

The width= 6cm

The two long sides are 8cm both so 8 + 8 = 16

And the two short sides are 3cm both so 3 + 3 = 6

So your length should be 16cm and your width 6cm

I HOPE THIS HELPS! ∧ ∧

⊂∵→ω←∵⊃

3 0

3 years ago

What is the coefficient of x2y3 in the expansion of (2x + y)5?

Zigmanuir [339]

Option C:

The coefficient of $x^{2} y^{3}$ is 40.

Solution:

Given expression:

$(2 x+y)^{5}$

Using binomial theorem:

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here $a=2 x, b=y$

Substitute in the binomial formula, we get

$(2x+y)^5=\sum_{i=0}^{5}\left(\begin{array}{l}5 \\i\end{array}\right)(2 x)^{(5-i)} y^{i}$

Now to expand the summation, substitute i = 0, 1, 2, 3, 4 and 5.

$$=\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}+\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1}+\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}+\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}$

$$+\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}+\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}$

Let us solve the term one by one.

$$\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}=32 x^{5}$

$$\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1} = 80 x^{4} y$

$$\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}= 80 x^{3} y^{2}$

$$\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}= 40 x^{2} y^{3}$

$$\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}= 10 x y^{4}$

$$\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}=y^{5}$

Substitute these into the above expansion.

$(2x+y)^5=32 x^{5}+80 x^{4} y+80 x^{3} y^{2}+40 x^{2} y^{3}+10 x y^{4}+y^{5}$

The coefficient of $x^{2} y^{3}$ is 40.

Option C is the correct answer.

5 0

3 years ago

What shape is created by the rotation and what is the

zlopas [31]

Answer:

<u>Option D: A cylinder with a circumference of about 50 units</u>

Step-by-step explanation:

The rest of the question is the attached figure.

The square shown has a perimeter of 32 units. The square is rotated about line k. What shape is created by the rotation and what is the approximate circumference of the base? Circumference of a circle: C = 2πr

===================================================

Given: the perimeter of the square = 32

perimeter of a square is four times the length of its side

So, the side length of square = 32/4 = 8 units

The square is rotated about line k.

So, it will form a cylinder with radius 8 units.

Circumference of a circle = 2 π r

Where, r is the radius of the circle.

Circumference of the base is C = 2 π * 8

∴ C = 16π = 16 * 3.14

∴ C = 50.26548 ≈ 50

The shape is created by the rotation is a cylinder with a circumference of about 50 units.

<u>So, the answer option is D.</u>

4 0

3 years ago

Please help! Will mark brainlyest. :)

Elden [556K]

Answer:

Step-by-step explanation:

base times hight times times 1/2

24X4X1/2

7 0

2 years ago

Read 2 more answers

Are the lines y=-2x and 2x+y=3. Are they paralell, perpendicular, or neither?

ELEN [110]

Answer:

They are parallel

7 0

3 years ago

Read 2 more answers