What is 9+10? answer in a complete sentence.

2 answers:

7 0

1. Set up the long addition.

9
+10
______

2. Calculate 9 + 0, which is 9.

 9
+10
______
9

3. Calculate 0 + 1, which is 1.

 9
+10
______
1 9

4. Therefore, 9 + 10 = 19.

oksian1 [2.3K]3 years ago

4 0

The answer is 19 10+9 would give you nineteen or you can just combine the numbers and replace the 0 with a 9

You might be interested in

Find a particular solution to y′′+6y′+5y=18te^(2t).

Andreas93 [3]

Answer:

idk just google it :)

Step-by-step explanation:

1. google it

6 0

3 years ago

FIND THE EXACT AREA OF THE SHADED PLEASE HELP ILL GIVE BRAINLIESTTTTTT

astra-53 [7]

1)
area of half of the circle: 628.32
are of parallelogram: 4000
Exact area of shaded: 3,371.68 cm squared.
The answer to the equation under the shape is: A = 4000 - 628.32 π in²

2)
area of both circles added together: 173.18
full area of rectangle: 220.5
Exact area of shaded: 47.32
The answer to the equation under the shape is: A = 220.5 - 173.18 π in²

Hope this helps!
Please give Brainliest!

8 0

2 years ago

If we have 9 candy bars and each student gets 1/3 candy barwith 10 students, how much of a sandwich does each student get? Expla

Rzqust [24]

Answer:

...................

Step-by-step explanation:

4 0

3 years ago

The probability that a student has a Visa card (event V) is .63. The probability that a student has a MasterCard (event M) is .1

Aleksandr-060686 [28]

Answer:

a) The probability that a student has either a Visa card or a MasterCard is 0.71.

b) V and M are not independent.

Step-by-step explanation:

Given : The probability that a student has a Visa card (event V) is 0.63. The probability that a student has a MasterCard (event M) is 0.11. The probability that a student has both cards is 0.03.

To find :

a) The probability that a student has either a Visa card or a MasterCard ?

b) In this problem, are V and M independent ?

Solution :

The probability that a student has a visa card(event V) is P(V)= 0.63

The probability that a student has a MasterCard (event M) is P(M)= 0.11

The probability that a student has both cards is $P(V \cap M)=0.03$