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1 year ago

How many faces, edges and vertices does the shape below have?

Mathematics

2 answers:

Alex777 [14]1 year ago

4 0

<h2><u>PENTAGONAL PYRAMID</u></h2>

<h3>Answer:</h3>

Faces = 6

Edges = 10

Vertices = 6

<h3>Explanation:</h3>

A <u>face</u> is any of the flat surfaces of a solid object, meaning that the pentagonal pyramid has got 6 faces in total; 5 triangles, and 1 pentagon (5+1=6)

An <u>edge</u> is a line segment where two faces meet, and they also join each vertex with another. So if we look at the base of the pentagonal pyramid (which is a pentagon) we can see that it has got 5 edges, and then, when we look at the edges that connect the triangles with eachother, there are 5 more edges, so 5+5=10.

A <u>vertex</u> is where two or more line segments (edges) meet. The base (pentagon) has 5 vertices, and at the top, where the 5 triangles' edges connect, there is another vertex (just 1). So 5+1=6.

patriot [66]1 year ago

3 0

This is a pentagonal prism

- it has 6 faces
- 6 vertices
- 10 edges

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Answer:

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Step-by-step explanation:

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3 years ago

What is the value of x in trapezoid ABCD? x=15 x=20 x=45 x=60

zvonat [6]

Answer:

A. <u><em>X = 15</em></u> is the correct answer.

Step-by-step explanation:

It's the only one that really makes sense.

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3 years ago

Read 2 more answers

En un triángulo rectángulo A es un ángulo agudo y Sen A = 4/5 ¿Cuál será el valor de Tan A?

Nonamiya [84]

Answer:

$\displaystyle \tan A=\frac{4}{3}$

Step-by-step explanation:

<u>Funciones Trigonométricas</u>

La identidad principal en trigonometría es:

$sen^2A+cos^2A=1$

Si sabemos que A es un ángulo agudo (que mide menos de 90°), su seno y coseno son positivos.

Dado que Sen A = 4/5, calculamos el coseno:

$cos^2A=1-sen^2A$

Sustituyendo:

$\displaystyle cos^2A=1-\left(\frac{4}{5}\right)^2$

$\displaystyle cos^2A=1-\frac{16}{25}$

$\displaystyle cos^2A=\frac{25-16}{25}$

$\displaystyle cos^2A=\frac{9}{25}$

Tomando raíz cuadrada:

$\displaystyle cos\ A=\sqrt{\frac{9}{25}}=\frac{3}{5}$

La tangente se define como:

$\displaystyle \tan A=\frac{sen\ A}{cos\ A}$

Substituyendo:

$\displaystyle \tan A=\frac{\frac{4}{5}}{\frac{3}{5}}$

$\displaystyle \tan A=\frac{4}{3}$

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3 years ago

A car motercycle leaves at noon from the same location, heading in the same direction. The average speed of the car is 30mph slo

alina1380 [7]

Answer:

speed of motorcycle = 40 mph

speed of car = 50 mph

Step-by-step explanation:

Here is the complete question

A car and a motorcycle leave at noon from the same location, heading in the same direction. The average speed of the car is 30 mph slower than twice the speed of the motorcycle. In two hours, the car is 20 miles ahead of the motorcycle. Find the speed of both the car and the motorcycle, in miles per hour.

Speed = distance / time

This question would be solved using simultaneous equation

let m = average speed of the motorcycle

c = average speed of the car

c = 2m - 30 equation 1

20 =(c - m) x 2 equation 2

insert equation 1 into equation 2 and divide through by 2

10 = (2m - 30) - m

solve for m

m = 40 mph

substitute for m in equation 1

2(40) - 20 = 50 mph

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3 years ago

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