Let's follow the transformations that happen to A, to get to A' and A''.
Point A is at (-5, -2)
It moves to (-5, 2) which is where A' is located. Note the x coordinate stays the same while the y coordinate flips from negative to positive. This must mean we applied a reflection over the x axis.
That rule in general is 
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Now compare A'(-5,2) and A''(1,4). We can shift A' 6 units to the right and then 2 units up so we move from A' to A''.
Algebraically this is stated as 
Whatever the x coordinate is, add 6 to it. For the y coordinate, we add on 2.
Applying that rule to B'(-1,2) gets us to

which is the proper location of B''
The same applies to moving C' to C''

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In summary, we started off by reflecting over the x axis. Then we applied the translation rule of "shift to the right 6 units, shift up 2 units".
In terms of algebra, combining the rules
and
will have us end up with 
<em><u>Perimeter=L+W×2
50+30×2=160.
</u></em>
Add 2z to both sides. you get
6k-2z+2z=12+2z
6k=2z+12
divide both sides by 6
6k/6=2z+12 divide by 6
your answer is k=1/3z+2
i hope it helps!
Answer:
Lol
Step-by-step explanation: