Find the coordinates of the points of intersection of the graph of y=13−x with the axes and compute the area of the right triang
le formed by this line and coordinate axes.
2 answers:
The x- and y-intercepts are both 13, so the area is ...
... A = (1/2)bh = (1/2)·13·13 = 169/2 = 84.5 . . . square units
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Solve for x when y=0 to find the x-intercept:
... 0 = 13 - x
... x = 13 . . . . . add x
Solve for y when x=0 to find the y-intercept:
... y = 13 - 0
... y = 13 . . . . . additive identity property of 0
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Answer:
1) 1 2)100 3)6.25.
Step-by-step explanation:
Any trinomial is of the form ax^2+bx+c .
To make the expression a perfect square we take half of b term then square it Add This is what we add to make the expression a perfect square.
1)Half of coefficient of x term is 1 .
Square it that is 1 is added to make it a perfect square.
2) Half of coefficient of x term that is 20÷2=10 .Square it that is 100 is added to make it a perfect square.
3) Half of coefficient of x that is 5÷2=2.5.Square it 6.25 is added to the expression to make it a perfect sqauare.