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3 years ago

What number should be added to -28 to make the sum 0

Mathematics

2 answers:

Romashka-Z-Leto [24]3 years ago

7 0

You would add 28 to -28 and you would get your answer of 0

HACTEHA [7]3 years ago

6 0

If you imagine a number line where 0 is in the middle, and all the negative numbers are on the left side of 0 and all the positive numbers are on the right side of 0, -28 will be 28 units across on the left side.

Therefore, to get back to 0, you need to go back 28 units (moving to the right), which is positive. Therefore, to make the sum 0, you need to add 28 to -28.

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Determine whether each set of numbers can be measure of the sides of a RIGHT triangle. Justify your answer.

Papessa [141]

Answer:

The side lengths cannot belong to a right triangle.

Step-by-step explanation:

This is a simple case of Pythagorean proof. If this triangle was a right triangle, 20^2 + 21^2 = 28^2. However, this is not the case. 20^2 + 21^2 = 841, which square root is 29.

If you forgot, the Pythagoren Theorem is: a^2 + b^2 = c^2.

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4 years ago

Hamburgers sell for 3 pounds for 6 dollars. if samantha buys 10 pounds for hamburgers how much will she pay

tamaranim1 [39]

You would start by 6÷3. This would tell you that for every proud of hamburger you pay $2.

Therefore multiply 10×2 and that equals 20.

Therefore, your answer is $20.

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3 years ago

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Lelechka [254]

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Step-by-step explanation:

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3 years ago

A random sample of 16 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 11 and the sample stand

Tpy6a [65]

Answer:

We conclude that the population mean is different from 10.5.

Step-by-step explanation:

We are given that a random sample of 16 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 11 and the sample standard deviation is 2.

We have to test the claim that the population mean is 10.5.

Let, NULL HYPOTHESIS, $H_0$ : $\mu$ = 10.5 {means that the population mean is 10.5}

ALTERNATE HYPOTHESIS, $H_a$ : $\mu \neq$ 10.5 {means that the population mean is different from 10.5}

The test statistics that will be used here is One-sample t-test;

T.S. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = 11

s = sample standard deviation = 2

$\mu$ = population mean

n = sample of values = 16

So, test statistics = $\frac{11-10.5}{\frac{2}{\sqrt{16} } }$ ~ $t_1_5$

= 1

Now, at 0.05 significance level, t table gives a critical value of 2.131 at 15 degree of freedom. Since our test statistics is way less than the critical value of t so we have insufficient evidence to reject null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the population mean is different from 10.5.

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4 years ago