Answer:
Step-by-step explanation:
+6 +6
You can't go any further s its b, NO SOLUTION.
Hope this helps :)
Let's say the side length of square A is x, which means the side length of square B is 2x.
Then, the area of square A can be written as , and the area of square B can be written as .
There's no diagram here with shaded region, so I'll just find the area of square A as a percentage of the area of square B:
= 1/4 = 25%
So, the answer is 25% (note this is the answer to the question: "express the area of square A as a percentage of the area of square B; there is no diagram showing me where the shaded area is, so I cannot answer the original question
Answer:
The equation of the quadratic graph is f(x)= - (1/8) (x-3)^2 + 3 (second option)
Step-by-step explanation:
Focus: F=(3,1)=(xf, yf)→xf=3, yf=1
Directrix: y=5 (horizontal line), then the axis of the parabola is vertical, and the equation has the form:
f(x)=[1 / (4p)] (x-h)^2+k
where Vertex: V=(h,k)
The directix y=5 must intercept the axis of the parabola at the point (3,5), and the vertex is the midpoint between this point and the focus:
Vertex is the midpoint between (3,5) and (3,1):
h=(3+3)/2→h=6/2→h=3
k=(5+1)/2→k=6/2→k=3
Vertex: V=(h,k)→V=(3,3)
p=yf-k→p=1-3→p=-2
Replacing the values in the equation:
f(x)= [ 1 / (4(-2)) ] (x-3)^2 + 3
f(x)=[ 1 / (-8) ] (x-3)^2 + 3
f(x)= - (1/8) (x-3)^2 + 3
Answer:
7 2/3 minutes
Step-by-step explanation:
We can write this equation in y = mx+b form
where m = 3 ft/min and b = -105 ft
x is the number of minutes and y is the depth
y = 3 * x -105
We want to find when y = -82
-82 = 3x -105
Add 105 to each side
-82+105 = 3x-105+105
23=3x
Divide by 3
23/3 = 3x/3
23/3=x
Changing into a mixed number
3 goes into 23 7 times with 2 left over
7 2/3 minutes
Answer:
61 + n = 82
Step-by-step explanation:
So the total number of candy is 82. This is the sum of each type of candy, i.e. 18 + 24 + 19 + n. So we have
18 + 24 + 19 + n = 82
61 + n = 82
( if we solve the equation we get n = 82 - 61 = 21)
Hope it helps and if it does please mark me brainliest;)
