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seropon [69]
2 years ago
10

Determine the period

Mathematics
1 answer:
True [87]2 years ago
8 0
To raise something upward with the force of a lever in order to remove, open, or look beneath it.
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Help help help and help
Alexus [3.1K]

Answer:

x= 8.5 and y= 2

Step-by-step explanation:

6 0
3 years ago
Plz help i will give branliest.
Salsk061 [2.6K]

Answer:

1/4

Step-by-step explanation:

5 0
3 years ago
Please help on this one plzzzz
deff fn [24]

We know that Angle Bisector Divides an Angle into Two Equal Angles.

As UP is the Angle Bisector of Angle U, It Divides Angle U into two Equal Parts they are Angle(1) and Angle(2)

⇒ Angle(1) = Angle(2)

Given Angle(1) = 5x + 10 and Angle(2) = 3x + 14

⇒ 5x + 10 = 3x + 14

⇒ 2x = 4

⇒ x = 2

⇒ Angle(1) = 5x + 10 = 5(2) + 10 = 10 + 10 = 20

So : Measure of Angle(1) is 20

8 0
3 years ago
3x-1/2 - 2(4+3x)/13 = 2
Gnesinka [82]

3x-1/2 - 2(4+3x)/13 = 2

distribute

3x -1/2 -8/13 -6x/13 =2

combine like terms

3x-6x/13 -1/2 -8/13 =2

multiply by 26 to get rid of the fractions (2*13)

26*(3x-6x/13 -1/2 -8/13) =2*26

78x - 12x -13 -16 = 52

66x -29 =52

add 29 to each side

66x =81

x = 81/66

divide top and bottom by 3

x=27/22

x = 1  5/22




5 0
3 years ago
What is the constant term in the expansion of $\left(\sqrt{x}+\dfrac5x\right)^{9}$?
PolarNik [594]

Answer:

(\sqrt{x})^{5}(5/x)^{4}

Step-by-step explanation:

Hi there.

Well, let's translate it from Latex. Then expanding it:

\left(\sqrt{x}+\dfrac5x\right)^{9}=    (\sqrt{x})^9(5/x)^{0} +(\sqrt{x})^{8}(5/x)^{1}+(\sqrt{x})^{7}(5/x)^{2} \\+(\sqrt{x})^{6}(5/x)^{3}+(\sqrt{x})^{5}(5/x)^{4}+(\sqrt{x})^{4}(5/x)^{5}\\+(\sqrt{x})^{3}(5/x)^{6}+(\sqrt{x})^{2}(5/x)^{7}+(\sqrt{x})^{1}(5/x)^{8}+(\sqrt{x})^{0}(5/x)^{9} =

\frac{\left(5+x^{\frac{3}{2}}\right)^9}{x^9}

Finding a constant term, in a Binomial has its cases.

In this case, there's no constant as a real number. Also, this an univariate binomial. So to find this Binomial expansion's constant term. We must follow this formula, (for a 9th degree) there are 10 terms:

n-2k=0\\10 -2k =0\\K=5th :\term\\

(\sqrt{x})^{5}(5/x)^{4}

Because this result satisfy a ratio.

y=\frac{c}{x}

Where c is the constant term, x is the first term of this binomial

8 0
3 years ago
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