Answer:
S(t) = 600*0.9^t
Step-by-step explanation:
At the beginning (t = 0) the sample has 600 grams. After 1 millennium from today (t = 1) the mass will be: 600 - 600*0.1 = 600*0.9. After 2 millennium from today (t = 2) the mass will be the 90% of the mass in the previous millenium, that is: 600*0.9*0.9 = 600*0.9^2. Analogously, at time = 3, sample's mass will be: 600*0.9^2*0.9 = 600*0.9^3. In a table format, that is
t m
0 600
1 600 - 600*0.1 = 600*0.9
2 600*0.9*0.9 = 600*0.9^2
3 600*0.9^2*0.9 = 600*0.9^3
Therefore, sample's mass in grams, S(t), where t refers to millennia from today is computed as follows: S(t) = 600*0.9^t
Answer:
2 percent hey
Step-by-step explanation:
Answer:
f(1) = 8
Common ratio: 0.5
Step-by-step explanation:
f(1) means the firs term in a sequence.
In the function f(n), represented by 8, 4, 2, 1, .., the first term is 8.
f(1) = 8
To find the common ratio, divide any term by the term before it.
We can use any two of the given terms in the sequence EXCEPT for 8 because it is the first term and does not have a term before it.
I choose to divide the second term by the first term:
4/8 = 1/2 = 0.5
Answer:
The answer is - a) 800
Step-by-step explanation:
In a periodic review system, we calculate the quantity of an item, a company has on hand at specified and fixed interval of time.
Given is : The target inventory level is 1000 units and the on-hand inventory level is 200 units.
So, the quantity will be =
units.
The answer is option A.
Well you could get 7 right
