The solutions appear to be
{π/2, 2π/3, 4π/3}.
_____
Replacing sin(2x) with 2sin(x)cos(x), you have
2sin(x)cos(x) +sin(x) -2cos(x) -1 = 0
sin(x)(2cos(x) +1) -(2cos(x) +1) = 0 . . . . factor by grouping
(sin(x) -1)(2cos(x) +1) = 0
This has solutions
sin(x) = 1
x = π/2and
2cos(x) = -1
cos(x) = -1/2
x = {2π/3, 4π/3}
For this case we have the following expression:
The first thing we must do is to rewrite the expression as the product of two binomials.
To do this, we add similar terms.
We have then:
Then, doing distributive property we have:
Adding similar terms:
Answer:
The simplified expression is:
Answer:
True
Step-by-step explanation:
This set is a function because every input value only has one output value.
The answer is 1/2
please see the attached picture for full solution
hope it helps
Good luck on your assignment
1. Yes they are congruent. You translate AB to move it over to CD. Specifically, shift 2 units to the right.
2. No, they are not congruent. QR is longer than MN. Congruent segments must be the same length.
3. No, they are not congruent. At first glance, they seem to be congruent after translation and reflection. However, XY is longer than UV, and those legs should be the same length for a pair of congruent triangles to be possible.
4. Yes they are congruent. You translate triangle ABC to move it over to triangle DEF (shift 1 to the left, 3 down).
