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3 years ago

Solve the inequality 2 less than or equal to x and negative 3 less than or equal to 6

Mathematics

1 answer:

boyakko [2]3 years ago

4 0

The answer is 2<x and -3<6

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Question in image please help quickly, I'm on a time limit :D

inn [45]

Answer:

By distance formula ,

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AB = \sqrt{(-1-5)^2 + (6-3)^2}$

$AB = \sqrt{36 + 9}$

$AB = \sqrt{45}$

$AB = 6.708$ (approx)

To give answer in 3 significant figures :

AB = 6.70

4 0

3 years ago

Write each literal term in exponential form.<br><br> abcbabc

qwelly [4]

Two a's, 3 b's, two c's, so a²b³c²

3 0

3 years ago

Find the mean of this set of numbers.<br><br> 7, –9, 6, –10, –13, –5

ivann1987 [24]

7+(-9)+6+(-10)+(-13)+(-5)=
7-9+6-10-13-5=
-24

mean is the sum of all the numbers divided by the total number of numbers within the data.

-24÷6=-4

The mean is -4.

5 0

3 years ago

Bob bought 16 packs of cola. Each pack had 8 cans. He drank 9 of the cans. How many cans are left?

grin007 [14]

Answer:

119 Cans Left

Step-by-step explanation:

If bob brought 16 packs of soda, and each pack had 8 cans, there would be 128 cans. This is because 1 pack is worth 8 cans.

16 × 8 = 128

128 - 9 = 119

Bob drank 9 of the cans, which is the same as subtracting from 128. This gives us the answer.

3 0

3 years ago

Daniel had 80 more stickers than Elle. He gave 1/4 of his stickers to Elle. She then gave 3/5 of her stickers to Daniel. In the

Pepsi [2]

Answer:

Daniel had 108 stickers at first

Step-by-step explanation:

Number of Daniel's stickers = d

Number of Elle's stickers = e

Since Daniel had 80 more stickers than Elle, d = 80 + e

e = d - 80

Daniel gave 1/4 of his stickers to Elle, Daniel is left with (d - d/4) = 3d/4

Elle now has e + d/4 = d - 80 + d/4 = (5d/4) - 80 = (5d - 320)/4

Elle now gave 3/5 of her remaining stickers to Daniel:

Elle now has:

$e_{new} = \frac{5d -320}{4} - \frac{3}{5} * \frac{5d -320}{4}\\\\e_{new} = \frac{5d -320}{4} - \frac{15d -960}{20}\\\\e_{new} = \frac{25d - 1600 - 15d + 960}{20} \\\\ e_{new} = \frac{10d-640}{20}$