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3 years ago

A positive number is A negative number is

Mathematics

1 answer:

marysya [2.9K]3 years ago

6 0

Answer:

A positive number is the opposite of a negative number witch is negative

ex: 1,2,3,4,5,6,7,8,9

A negative number is the opposite of a positive number

ex: -1,-2,-3,-4,-5,-6,-7,-8,-9

You might be interested in

How many significant digits are there in the number 0.0102?

Darina [25.2K]

Significant digits are all digits, after the comma, excluding the first if this first is Zero

So the number of significant digits is 3 (1,0,2)

3 0

3 years ago

Read 2 more answers

Opal made t-shirts. It cost $39 to print one shirt. It costs $75 for 10 shirts. Write an equation to represent the

RUDIKE [14]

Answer:

39 X 10=75

Step-by-step explanation:

‍♀️

4 0

2 years ago

Please answer this correctly without making mistakes I want ace expert and genius people to answer this correctly without making

soldi70 [24.7K]

Answer:

yz + z = -22

Step-by-step explanation:

Ok so you are already the number that y = 10 and z = -2. You will plug these number in the equation in order to find the answer. :-

y = 10 and z = -2

yz + z

10(-2) - 2

-20 - 2

-22

Hope this helps, thank you :) !!

6 0

2 years ago

Suppose on a certain planet that a rare substance known as Raritanium can be found in some of the rocks. A raritanium-detector i

aleksandrvk [35]

Answer:

0.967 = 96.7% probability the rock sample actually contains raritanium

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Positive reading

Event B: Contains raritanium

Probability of a positive reading:

98% of 13%(positive when there is raritanium).

0.5% of 100-13 = 87%(false positive, positive when there is no raritanium). So

$P(A) = 0.98*0.13 + 0.005*0.87 = 0.13175$

Positive when there is raritanium:

98% of 13%

$P(A) = 0.98*0.13 = 0.1274$

What is the probability the rock sample actually contains raritanium?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.1274}{0.13175} = 0.967$

0.967 = 96.7% probability the rock sample actually contains raritanium

7 0

2 years ago

Solve the proportion 4/k+3=8/14

MatroZZZ [7]

Cross multiply to get 8k+24=56 then solve for k so subtract 24 from each side to get 8k=32 so k=4

7 0

3 years ago

Read 2 more answers