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SVETLANKA909090 [29]
3 years ago
9

Bus A travels according to the function y = 125/5x where y is distance traveled in miles and x is time in hours. Bus B travels a

ccording to the graph below, where the distance y is a function of time x. Which bus travels faster? Include all necessary calculations in your final answer.

Mathematics
1 answer:
Yuki888 [10]3 years ago
6 0

Answer:

Bus B travel faster

Step-by-step explanation:

The graph of the question in the attached figure

we know that

the linear equation in slope intercept form is equal to

y=mx+b

where

m is the slope

b is the y-intercept

x ---> is the time in hours

y ---> is the distance in miles

In this problem we have

Bus A

y=\frac{125}{5}x

The slope of the linear equation represent the speed of the bus

so

The speed of bus A is

\frac{125}{5}=25\ miles/hour

Bus B

Find  the slope

take two points from the graph

(0,0) and (3,200)

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute

m=\frac{200-0}{3-0}

m=66.67\ \frac{miles}{hour}

Compare the slope Bus A with the slope Bus B

66.67\ \frac{miles}{hour} > 25\ \frac{miles}{hour}

therefore

Bus B travel faster

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dalvyx [7]

Answer:

6

Step-by-step explanation:

Straight line is 180

square = right angle=90

180-90=90

5x+(x+54)=90

6x+54=90

6x=36

x=6

Hope this helps :D

6 0
3 years ago
4/9+3/10= what's the answer please​
Marta_Voda [28]

Answer:

67/90

Step-by-step explanation:

no explanation

3 0
3 years ago
Read 2 more answers
A random sample of 20 students yielded a mean of ¯x = 72 and a variance of s2 = 16 for scores on a college placement test in mat
Helen [10]

Answer:

The 98% confidence interval for the variance in the pounds of impurities would be 8.400 \leq \sigma^2 \leq 39.827.

Step-by-step explanation:

1) Data given and notation

s^2 =16 represent the sample variance

s=4 represent the sample standard deviation

\bar x represent the sample mean

n=20 the sample size

Confidence=98% or 0.98

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

On this case the sample variance is given and for the sample deviation is just the square root of the sample variance.

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=20-1=19

Since the Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.01,19)" "=CHISQ.INV(0.99,19)". so for this case the critical values are:

\chi^2_{\alpha/2}=36.191

\chi^2_{1- \alpha/2}=7.633

And replacing into the formula for the interval we got:

\frac{(19)(16)}{36.191} \leq \sigma^2 \leq \frac{(19)(16)}{7.633}

8.400 \leq \sigma^2 \leq 39.827

So the 98% confidence interval for the variance in the pounds of impurities would be 8.400 \leq \sigma^2 \leq 39.827.

7 0
3 years ago
Perform the indicated operation and write the result in the form a + bi. i(5 - i) + 2i (i + 6) the
Nikitich [7]

i(5 - i) + 2i (i + 6) =

distribute

5i - i^2 +2i^2 +12i

5i - (-1) +2 (-1) +12i

5i +1 -2 +12i

-1+17i

8 0
3 years ago
Read 2 more answers
A science teacher has a supply of 50% sugar solution and a supply of 80% sugar solution. How much of each solution should the te
mash [69]
How much of each solution should the teacher mix together to get 105 ML of 60% sugar solution for an experiment?

1. Look at how 60% is closer to the solution of lower concentration (50%). You can deduce that you will be mixing a higher volume of the 50% solution.

2. All 4 answers add up to 105ml.

3. The intuitive answer is the first option:
70 ML of the 50% solution and 35 ML of the 80% solution

4. Let's check whether point 3 is true.
70ml/105ml X 0.5 + 35ml/105ml X 0.8 = (35 + 28)/105= 63/105= 60% / 105 ml = 105ml of 60% sugar solution
3 0
3 years ago
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