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vladimir2022 [97]
3 years ago
13

How to order the following fractions 3/4 9/16 3/16 7/8 3/8

Mathematics
2 answers:
Dimas [21]3 years ago
7 0
Comparison of fractions is easiest when they all have a common denominator, in this case we can make them all have a common denominator of 16...

12/16, 9/16, 3/16, 14/16, 6/16 so from least to greatest...

3/16, 3/8, 9/16, 3/4, 7/8
Andreas93 [3]3 years ago
7 0
3/4 = 0.75, 9/16 = 0.5625, 3/16 = 0.1875, 7/8 = 0.875, 3/8 = 0.375

Least to greatest:

3/16, 3/8, 9/16, 3/4, 7/8

Greatest to least:

7/8, 3/4, 9/16, 3/8, 3/16
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Hey there!

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4 0
3 years ago
Read 2 more answers
In circle G with m \angle FGH= 86m∠FGH=86 and FG=16FG=16 units, find the length of arc FH. Round to the nearest hundredth.
Igoryamba

Answer:

13.96

Step-by-step explanation:

50/ 360 (2π16)

7 0
2 years ago
A coin will be tossed three times, and each toss will be recorded as heads (H) or tails (T). Give the sample space describing al
cricket20 [7]

Answer:

Sample space:

{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

Third toss is heads:

{HHT, HTT, THT, TTT}

First toss is heads, second tails and third heads:

{HTH}

Explanation:

In order to find the sample space we need to write all the possible outcomes from tossing the coin three times.You can start by writting all the possible outcomes for the first toss being a head and finish with all the possible outcomes for the first toss being Tails. The number of elements in the sample space can be found by multiplying the possible outcomes of each toss together, so 2*2*2=8

{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

For the third toss being heads we will have one restriction this time. Which is that the third toss is Tails. You can take the elements from the sample space where the third element is a tails. In this case, the number of elements can be calculated by multiplying the possible outcomes for only the first two tosses 2*2=4

{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

For first toss is heads, second tails and third heads there is only one possible way for you to get this outcome so there is only one element to this set.

{HTH}

4 0
2 years ago
What value of k will result in the quadratic having one rational solution if 4x2+kx+4=0?
PtichkaEL [24]

The value of 'k' in the quadratic Equation    4x^{2}+kx+4=0 having one rational solution is k is 8.

<h3>What is a Quadratic Equation?</h3>
  • Quadratic equations are the polynomial equations of degree 2 in one variable of the type f(x) = ax^{2} + bx + c = 0 where a, b, c, ∈ R and a ≠ 0.
  • The standard form of a quadratic equation is ax^{2} + bx + c = 0 .

Here, the given equation is  4x^{2}+kx+4=0

By comparing the given equation with the standard form of the quadratic equation we get,

a = 4

b = k

c = 4

The given quadratic is having one rational solution, which means b^{2} -4ac=0

Therefore,

k^{2} -4 \times 4\times4=0\\k^{2} -64=0\\k^{2} =64\\k=\sqrt{64} \\k=8

Therefore, the value of k is 8.

Learn more about the quadratic equation is brainly.com/question/8649555

#SPJ4

7 0
1 year ago
A circle P is circumscribed about a regular hexagon ABCDEF
DanielleElmas [232]

Answer:the answer will be D

5 0
3 years ago
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