1. 55
2. N/A - Sorry. I can’t see the numbers properly.
3. 180
Answer:
<em>The first step is to determine the average
</em>
![x= \frac{0,6+0,7+ 0,7+0,3+0,4+ 0,5+ 0,4 +0,2}{8}\\\ x= 0,475](https://tex.z-dn.net/?f=x%3D%20%5Cfrac%7B0%2C6%2B0%2C7%2B%200%2C7%2B0%2C3%2B0%2C4%2B%200%2C5%2B%200%2C4%20%2B0%2C2%7D%7B8%7D%5C%5C%5C%20x%3D%200%2C475)
<em>The exercise says it’s a normal distribution: (n=8)</em>
![s^{2}= \frac{1}{n-1} ((0,6.x)^2+2(0,7-x)^2+(0.3-x)^2+2(0.4-x)^2+(0.5-x)^2+(0.2-x)^2)\\\ \frac{1}{7}*0,235 = 0,0336 \\\\ s= 0183](https://tex.z-dn.net/?f=s%5E%7B2%7D%3D%20%5Cfrac%7B1%7D%7Bn-1%7D%20%28%280%2C6.x%29%5E2%2B2%280%2C7-x%29%5E2%2B%280.3-x%29%5E2%2B2%280.4-x%29%5E2%2B%280.5-x%29%5E2%2B%280.2-x%29%5E2%29%5C%5C%5C%20%5Cfrac%7B1%7D%7B7%7D%2A0%2C235%20%3D%200%2C0336%20%5C%5C%5C%5C%20s%3D%200183)
<em>According to the exercise, the mean is equal to 0,5 then the value of t of the distribution can be obtained
</em>
<em />
![t= \frac{x-u}{\frac{s}{\sqrt{n} }}\\\ t= \frac{0,475 - 0,5}{0,183}\\\ t= -0,3860](https://tex.z-dn.net/?f=t%3D%20%5Cfrac%7Bx-u%7D%7B%5Cfrac%7Bs%7D%7B%5Csqrt%7Bn%7D%20%7D%7D%5C%5C%5C%20t%3D%20%5Cfrac%7B0%2C475%20-%200%2C5%7D%7B0%2C183%7D%5C%5C%5C%20%20t%3D%20-0%2C3860)
<em>The variable t has 7 grade to liberty, we calculate the p-value as:
</em>
![2* P(t < - 0,3860)= \\\ 2* 0,3554 = 0,7108](https://tex.z-dn.net/?f=2%2A%20P%28t%20%3C%20-%200%2C3860%29%3D%20%5C%5C%5C%202%2A%200%2C3554%20%3D%200%2C7108)
This value is very high, therefore the hypothesis is not rejected
Answer:
The correct option is A.
Step-by-step explanation:
The first line passing through the points (-6,2) and (-6,0).
The slope of a line is
![m=\frac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
The slope of first line is
![m_1=\frac{0-2}{-6-(-6)}=\infty](https://tex.z-dn.net/?f=m_1%3D%5Cfrac%7B0-2%7D%7B-6-%28-6%29%7D%3D%5Cinfty)
The second line passing through the points (0,-4) and (-1,1). The slope of second line is
![m_2=\frac{1-(-4)}{-1-0}=-5](https://tex.z-dn.net/?f=m_2%3D%5Cfrac%7B1-%28-4%29%7D%7B-1-0%7D%3D-5)
The third line passing through the points (0,-6) and (2,-6). The slope of third line is
![m_3=\frac{-6-(-6)}{2-0}=0](https://tex.z-dn.net/?f=m_3%3D%5Cfrac%7B-6-%28-6%29%7D%7B2-0%7D%3D0)
The fourth line passing through the points (0,6) and (-3,-7). The slope of fourth line is
![m_4=\frac{-7-6}{-3-0}=\frac{13}{3}](https://tex.z-dn.net/?f=m_4%3D%5Cfrac%7B-7-6%7D%7B-3-0%7D%3D%5Cfrac%7B13%7D%7B3%7D)
Since the slope of a vertical line is infinity, Therefore option A is correct.
10 good reasons why lying can b helpful