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yarga [219]
3 years ago
6

Please help me ASAP! Worth 11 points

Mathematics
2 answers:
alexandr402 [8]3 years ago
7 0
Yup he's got it right niceee job
saul85 [17]3 years ago
5 0

Answer:

x axis, then translate x+6, y+1

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Daniel is creating a scale drawing of her room. the rectangular room measures20 1/2 ft. by 25 ft. if her drawing uses the scale
zavuch27 [327]
1 in = 2 ft

20.5 ft = 10.25 in
25 ft = 17.5 in

8.5 in and 11 in. no, the drawing will not fit, because the proportions is larger than 8.5 in and 11 in. 

hope this helps


5 0
3 years ago
Read 2 more answers
What is the arc length if θ = 7 pi over 4 and the radius is 5?
PolarNik [594]

The formula for arc length is:

s= r∅

Given that ∅= 7π/4

and r= 5

Therefore, arc length s= 7π/4 *5 = 35π/4

4 0
3 years ago
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Please give me the correct answer ​
Marat540 [252]
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5 0
3 years ago
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Please help someone
DiKsa [7]

The first equation is x = -1

The second and third equations are no solution

The third equation is all rel numbers.


We can tell each one by solving them. In the first one, you get the following.


4 + x = -8x - 5 ----> Add 8x to both sides

4 + 9x = -5 ----> Subtract 4 from both sides

9x = -9 ----> Divide both sides by 9

x = -1


For the middle two, when you attempt to solve, you get untrue statements. This shows there are no solutions. See the example below.


7 + 2x = 2x - 7 ----> Subtract 2x from both sides

7 = -7 (UNTRUE)


And for the last one, each term cancels out, which shows that we have all real solutions.


-3x + 3 = 3( 1 - x) ----> Distribute the 3

-3x + 3 = 3 - 3x ----> Add 3x to both sides

3 = 3 (TRUE)

8 0
3 years ago
What is the distance to the Earth's Horizon from point P? Enter enter the decimal in the Box round only your final answer to the
Tasya [4]

Answer:

<h2>The distance to the Eath's Horizon from point P is 352.8 mi, approximately.</h2>

Step-by-step explanation:

You observe the problem from a graphical perspective with the image attached.

Notice that side x is tangent to the circle, which means is perpendicular to the radius which is equal to 3,959 mi.

We have a right triangle, that means we need to use the Pythagorean's Theorem, to find the distance to the Earth's Horizon from point P.

The hypothenuse is 3959 + 15.6 = 3974.6 mi.

(3974.6)^{2}=x^{2}  +(3959)^{2} \\x^{2} =15,797,445.16 - 15,673,681\\x=\sqrt{123,764.16} \approx 351.8

Therefore, the distance to the Eath's Horizon from point P is 352.8 mi, approximately.

4 0
3 years ago
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