Question

write a real word problem that can be represented by the equation ( 12 + 14 ) x h / 2 = 52. Then solve the problem.

Answer 1

Explanation:

The area of a trapezoid is given by:

$A=\frac{(B_{1}+B_{2})h}{2} \\ \\ \\ A;Area \\ \\ B_{1}:First \ base \\ \\ B_{2}=Second \ base \\ \\ h:Heigth$

So given the equation:

$\frac{( 12 + 14 )h}{2} = 52$

We can write a real problem as:

The bases of a trapezoid are $12cm \ and \ 14cm$ and the area of it is $52cm^2$. What is the height of the trapezoid?

Solving:

$\frac{( 12 + 14 )h}{2} = 52 \\ \\ 26h=104 \\ \\ h=\frac{104}{26} \\ \\ h=4cm$

Finally, the height of the trapezoid is 4cm