Answer:
<h2>

</h2>
<h2> </h2><h2>

</h2><h2>
</h2><h2>

</h2><h3>
</h3><h3>

</h3>
solution,




<h2>
</h2><h2 />
Hope this helps...
Good luck on your assignment..
Answer:
I think it is 3.1
Step-by-step explanation:
make me brainlyest pls
Answer:



Step-by-step explanation:
We know that:
Only employees are hired during the first 3 days of the week with equal probability.
2 employees are selected at random.
So:
A. The probability that an employee has been hired on a Monday is:
.
If we call P(A) the probability that 2 employees have been hired on a Monday, then:

B. We now look for the probability that two selected employees have been hired on the same day of the week.
The probability that both are hired on a Monday, for example, we know is
. We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.
So
.
C. If the probability that two people have been hired on a specific day of the week is
, then the probability that 7 people have been hired on the same day is:

D. The probability is
. This number is quite close to zero. Therefore it is an unlikely bastate event.
Answer:
A, C, E are your answers
Step-by-step explanation:
Answer:
5.2kg = 5,200 grams
Step-by-step explanation:
I hope it helps