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2 years ago

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1 answer:

Bumek [7]2 years ago

5 0

Answer:

wat?

Step-by-step explanation:

merry christmas....yey!!

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Expand the following:<br> a) x(x + 2)<br> b) x(2x - 5)<br> c) 2x(3x + 4)<br> d) 6x(x - 2)

TEA [102]

Answer:

<h2> $a. \: {x}^{2} + 2$ </h2>

<h2> </h2><h2> $b. \: 2 {x}^{2} - 5x$ </h2><h2> </h2><h2> $c. \: 6 {x}^{2} + 8x$ </h2><h3> </h3><h3> $d. \: 6 {x}^{2} - 12x$ </h3>

solution,

$a. \: x(x + 2) \\ \: \: = x \times x + 2 \times x \\ \: \: = {x}^{2} + 2x$

$b . \: x(2x - 5) \\ \: = x \times 2x - x \times 5 \\ \: \: = 2 {x}^{2} - 5x$

$c. \: 2x(3x + 4) \\ \: = 2x \times 3x + 2x \times 4 \\ \: \: = 6 {x}^{2} + 8x$

$d. \: 6x(x - 2) \\ \: \: = 6x \times x - 6x \times 2 \\ \: \: = 6 {x}^{2} - 12x$

<h2> </h2><h2 />

Hope this helps...

Good luck on your assignment..

4 0

2 years ago

Which expression is equivalent to 4/9 x 7

Romashka [77]

Answer:

I think it is 3.1

Step-by-step explanation:

make me brainlyest pls

8 0

2 years ago

Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar

horsena [70]

Answer:

$P(A) = \frac{1}{9}$

$P(B) = \frac{1}{3}$

$P(C) = \frac{1}{729}$

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

$P(M) = \frac{1}{3}$ .

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

$P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}$

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is $P(A) = \frac{1}{9}$ . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

So

$P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}$ .

C. If the probability that two people have been hired on a specific day of the week is $3(\frac{1}{3}) ^ 2$ , then the probability that 7 people have been hired on the same day is:

$P(C) = (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7\\\\P(C) = \frac{1}{729}$

D. The probability is $\frac{1}{729}$ . This number is quite close to zero. Therefore it is an unlikely bastate event.

6 0

2 years ago

Which of these would earn the same interest as a $150 principal at 4% annual interest for 2 years? Select all that apply.

olga nikolaevna [1]

Answer:

A, C, E are your answers

Step-by-step explanation:

7 0

3 years ago

How many meters are the<br>Convert 5.2kg to grams.<br>

Misha Larkins [42]

Answer:

5.2kg = 5,200 grams

Step-by-step explanation:

I hope it helps

6 0

2 years ago