Answer:
There wouldn't be a slope. It would be 0/5
Step-by-step explanation:
6 - 6 = 0
2 + 3 = 5
0/5 isn't a slope.
The gaps in the area needs to be closed so the data you use is lenient
Answer:
0, 1.32
Step-by-step explanation:
16cos(t)*sin(t)=4sin(t)
cos(t)=1/4 or sin(t)=0
t=1.32 or 0
The data below shows the average number of text messages sent daily by a group of people: 7, 8, 4, 7, 5, 2, 5, 4, 5, 7, 4, 8, 2,
enot [183]
It all depends. You've given us an incredibly vague question.
The outlier could be a number that's low or quite high. Also, outliers
shouldn't really contribute towards the value of the mean, median or
range related to a group of data.
They are called outliers because they are bizarre results or numbers
and should be detached from groups of data. Outliers by definition
are abnormalities or anomalies.
I'd say outliers don't really change anything, unless you actually want
to give them credibility or weight.
Large outliers can inflate the value of means, medians and ranges.
Small outliers will invariably deflate the value of means and medians.
Answer: 6 students
What we know:
Students: 24
Students who play checkers: 
Students who also play sudoku:
of the
24 ÷ 3 = 8, so 8 × 2 = 16 (students who play checkers)
× 2 = 
So the answer is,
6 students play both checkers and sudoku
