2 1/3+5 5/16+ 2/7 is approximately equal to?
2 answers:
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Answer:
3
Step-by-step explanation:
Given:
Team heights (inches):
61, 57, 63, 62, 60, 64, 60, 62, 63
To find: IQRs (interquartile ranges) of the heights for the team
Solution:
A quartile divides the number of terms in the data into four more or less equal parts that is quarters.
For a set of data, a number for which 25% of the data is less than that number is known as the first quartile
For a set of data, a number for which 75% of the data is less than that number is known as the third quartile
Terms in arranged in ascending order:
Number of terms = 9
As number of terms is odd, exclude the middle term that is 62.
is median of terms
Number of terms (n) = 4
Median =
So,
So, 25% of the heights of a team is less than 60 inches
is the median of terms
Median =
So,
So, 75% of the heights of a team is less than 63 inches
Interquartile range =
The interquartile range is a measure of variability on dividing a data set into quartiles.
The interquartile range is the range of the middle 50% of the terms in the data.
So, 3 is the range of the middle 50% of the heights of the students.