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hram777 [196]
3 years ago
12

How would you rewrite x^(9/7) ???

Mathematics
1 answer:
Anastaziya [24]3 years ago
3 0

The given expression is

x^{9/7}

We can write it in radical form, and the denominator of the exponent became the power of the radical. That is

x^{9/7} = \sqrt[7]{x^9}

And

\sqrt[7]{x^9} = \sqrt[7]{x^7*x^2}

We can also write it as

\sqrt[7]{x^7}*\sqrt[7]{x^2} = x \sqrt[7]{x^2}

And that's the simplified form of the given exponential form .

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1980/55 = AHW

36 = AHW

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Put 0 in the box.

Step-by-step explanation:

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3 years ago
Can I please get Help with this math problem please
kifflom [539]

Answer:

AB=16

BC=15

AC=12

PQ=12

QR=12

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Step-by-step explanation:

well you know that the perimeter is the sum of all sides

so we have

(2x)+(2x+4)+(2x+3)=(2x)+(2x)+(3x+1)\\\\2x+2x+4+2x+3=2x+2x+3x+1\\\\(2x+2x+2x)+(4+3)=(2x+2x+3x)+(1)\\\\6x+7=7x+1\\\\6x+7-1=7x\\\\6x+6=7x\\\\6=7x-6x\\\\x=6

so the sides are:

AB=2x+4=2(6)+4=12+4=16\\\\AB=16

BC=2x+3=2x+4-1=16-1=15\\\\BC=15

AC=2x=2(6)=12\\\\AC=12

PQ=2x=12\\\\PQ=12

QR=2x=12\\\\QR=12

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So there you are.

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8m²n³-24m²n²+4m³n<br> how do I factor out the GCF
mariarad [96]

Answer:

8 {m}^{2}  {n}^{3}  - 24 {m}^{2} {n}^{2}   + 4 {m}^{3}n = 4 {m}^{2} n(2 {n}^{2}  - 6n + m)

Step-by-step explanation:

The given expresion is

8 {m}^{2}  {n}^{3}  - 24 {m}^{2} {n}^{2}   + 4 {m}^{3}n

Observe that 4 is common to 8,-24, and 4

Observe also that, m²n is common to all the terms.

Hence the GCF is:4m²n

We factor the GCF to get;

8 {m}^{2}  {n}^{3}  - 24 {m}^{2} {n}^{2}   + 4 {m}^{3}n = 4 {m}^{2} n(2 {n}^{2}  - 6n + m)

6 0
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