7th grade help me please:)

Simplify quantity 1 over 36 minus 1 over x squared all over 1 over 6 plus 1 over x.

Ne4ueva [31]

[ (1 / 36) - (1 / x²) ] / [ (1 / 6) + (1 / x) ]

[ (x² - 36) / 36x² ] / [ (x + 6) / 6x ]

remember that:
x² - 36 = (x + 6)(x - 6)

so

[ (x+6)(x-6) / 36x² ] / [ (x + 6) / 6x ]

[ (x+6)(x-6) / 36x² ] * [ 6x / (x + 6) ]

6x / 36x² = 1 / 6x

[ (x+6)(x-6) / 6x ] * [ 1 / (x+6) ] -------------------- > (x - 6) / 6x

The answer is (x - 6) / 6x

7 0

3 years ago

Explain the steps to find the difference of the question below

nevsk [136]

Step-by-step explanation:

1 -5/8

lcm=8

8-5=3

3/8

mark me brainliest or else I will report this question.

3 0

3 years ago

The rates of on-time flights for commercial jets are continuously tracked by the U.S. Department of Transportation. Recently, So

tatyana61 [14]

Answer:

The probability that at least 13 flights arrive late is 2.5196 $\times 10^{-6}$ .

Step-by-step explanation:

We are given that Southwest Air had the best rate with 80 % of its flights arriving on time.

A test is conducted by randomly selecting 18 Southwest flights and observing whether they arrive on time.

The above situation can be represented through binomial distribution;

$P(X = x) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.........$

where, n = number of trials (samples) taken = 18 Southwest flights

r = number of success = at least 13 flights arrive late

p = probability of success which in our question is probability that

flights arrive late, i.e. p = 1 - 0.80 = 20%

Let X = Number of flights that arrive late.

So, X ~ Binom(n = 18, p = 0.20)

Now, the probability that at least 13 flights arrive late is given by = P(X $\geq$ 13)

P(X $\geq$ 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18)

= $\binom{18}{13}\times 0.20^{13} \times (1-0.20)^{18-13}+ \binom{18}{14}\times 0.20^{14} \times (1-0.20)^{18-14}+ \binom{18}{15}\times 0.20^{15} \times (1-0.20)^{18-15}+ \binom{18}{16}\times 0.20^{16} \times (1-0.20)^{18-16}+ \binom{18}{17}\times 0.20^{17} \times (1-0.20)^{18-17}+ \binom{18}{18}\times 0.20^{18} \times (1-0.20)^{18-18}$

= $\binom{18}{13}\times 0.20^{13} \times 0.80^{5}+ \binom{18}{14}\times 0.20^{14} \times 0.80^{4}+ \binom{18}{15}\times 0.20^{15} \times 0.80^{3}+ \binom{18}{16}\times 0.20^{16} \times 0.80^{2}+ \binom{18}{17}\times 0.20^{17} \times 0.80^{1}+ \binom{18}{18}\times 0.20^{18} \times 0.80^{0}$

= 2.5196 $\times 10^{-6}$ .

7 0

3 years ago

Write an expression to represent the original tiles then simplify.

dmitriy555 [2]

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5 0

2 years ago

2). You are to construct the walls for the storage building that will be 8' high; using the

yulyashka [42]

Answer:28

Step-by-step explanation:

7 0

2 years ago