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REY [17]
3 years ago
11

Find an equation of a parabola with a vertex at the origin of directrix Y = -2.5

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
8 0

Answer:

y=\frac{1}{10}x^2

Step-by-step explanation:

Since the directrix is y=-2.5, it means the axis of the parabola is parallel to the y-axis.


Also, the vertex is at the origin so the parabola opens upwards.


The equation of a parabola with these properties is of the form x^2=4py, where |p|=2.5,that is the distance between the vertex and the directrix.


\Rightarrow p=-2.5\:or\:2.5.


Since the parabola opens upwards, we choose p=2.5.


The equation of the parabola now becomes,

x^2=4(2.5)y


\Rightarrow x^2=10y


Or

y=\frac{1}{10}x^2


See graph


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Given that f(x) = ax – 5 and f(4) = 15, determine the value of a.
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The given function is:

f(x)  =  ax  -  5

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