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disa [49]
2 years ago
7

What is the solution to the equation: 3(-2x - 1) = 2(x + 5)?

Mathematics
1 answer:
Molodets [167]2 years ago
3 0

C

remove the parentheses

move the terms

collect like terms and calculate

divide both sides

and you get -13/8

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Write these numbers from least to greatest -0.615, -5/8, -0.62
inna [77]
Well -5/8 as a decimal would be -0.625.
So, the order would be -0.615 -0.62(0) and then -5/8 (or -0.625).
You could easily search up 5/8 as a decimal :)
5 0
3 years ago
Let u = <3, -1>, v = <-6, -6>. Find 9u + 2v.
Gnom [1K]
9u means you're multiplying 9 into that vector, both components.  Same with the 2v.  9*3 = 27 and 9*-1 = -9, so your new vector u is <27, -9>.  Now let's do v.  2* -6 (twice) = -12, so your new v vector is <-12, -12>.  Add those together now, first components of each and second components of each.  27 + (-12) = 15; -9+(-12)=-21.  So the addition of those gives us a final vector with a displacement of <15, -21>
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3 years ago
There are 1295 students attending a small university there are 714 woman in rolled what percentage of students are woman
MatroZZZ [7]

Answer:

Approximately 55% of enrolled students are women.

Step-by-step explanation:

To find the percentage of a given set of data, you need to divide the number of actual students by the total number of students.  In this case, they are wanting the percentage of just women students at the university:

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4 0
3 years ago
Question 15 (5 points)
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8 0
2 years ago
Given the definitions of f(x) and g(x) below, find the value of g( f(-5)).
tensa zangetsu [6.8K]

Answer:

we conclude that:

  • g(f(-5)) = 30

Step-by-step explanation:

Given

f(x) = x+9

g(x) = x² + 7x – 14

To determine

g(f(-5)) = ?

First, we need to find f(-5)

f(x) = x+9

substitute x = -5

f(-5) = (-5)+9

f(-5) = -5+9

f(-5) = 4

so

g(f(-5)) = g(4)

Now, we need to find g(4)

g(x) = x² + 7x – 14​

substitute x = 4

g(4) = (4)² + 7(4) - 14

g(4) = 16 + 28 - 14

g(4) = 30

i.e.

g(f(-5)) = g(4) = 30

Therefore, we conclude that:

  • g(f(-5)) = 30
7 0
3 years ago
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