Answer:
80%
Step-by-step explanation:
Focus on the important parts of the problem:
The present salary is 25% more than the previous salary.
previous = % of present ?
<u>Use a mock/fake situation.</u> Let' say the previous salary is $100.
100 = % of present
Present salary is $100 increased by 25%.
$100 X 1.25 = $125
100 = % of 125
Solve this in decimal form (convert it to a percentage later).
Let x be the percentage in decimal form.
100 = 125x
100/125 = x Isolate "x" by dividing by sides by 125
x = 0.80
Convert 0.80 to percentage by multiplying by 100.
0.80 X 100 = 80%
When comparing two things using percentage, 100% is the same. Less than 100% is less and more than 100% is more.
Since his previous salary was less than his present salary, this answer makes sense.
Therefore his previous salary was 80% of his present salary.
<span><span>y = 2 + 2sec(2x)
The upper part of the range will be when the secant has the smallest
positive value up to infinity.
The smallest positive value of the secant is 1
So the minimum of the upper part of the range of
y = 2 + 2sec(2x) is 2 + 2(1) = 2 + 2 = 4
So the upper part of the range is [4, )
The lower part of the range will be from negative infinity
up to when the secant has the largest negative value.
The largest negative value of the secant is -1
So the maximum of the lower part of the range of
y = 2 + 2sec(2x) is 2 + 2(-1) = 2 - 2 = 0
So the lower part of the range is (, 0].
Therefore the range is (, 0] U [4, )
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Answer:
Step-by-step explanation:
there is no solution:
6-2(3-2x) = -4(3-x)
6-6+4x= -12+4x
4x= -12+4x
0=-12
Answer:
Step-by-step explanation:
A is the correct answer
