All categories

2 years ago

What is the solution to the equation: 3(-2x - 1) = 2(x + 5)?

Mathematics

1 answer:

Molodets [167]2 years ago

3 0

remove the parentheses

move the terms

collect like terms and calculate

divide both sides

and you get -13/8

You might be interested in

There is a L-shaped sidewalk that is 158 meters long. By cutting across the lawn, the

NikAS [45]

Answer:

Each side of the L-shaped sidewalk is 126 m and 32m respectively.

Step-by-step explanation:

Given:

Total length of the sidewalk = 158 meters

Cutting across the lawn the distance = 130 meters

The L-shaped lawn will be treated as a right angled triangle.

So the 130 m distance is the hypotenuse here.

Let one side of the L-shaped lawn be 'x' meter so the another side will be (158-x) meters.

Applying Pythagoras formula.

$(Hypotenuse)^2=(height)^2+(base)^2$

So,

⇒ $(130)^2=x^2 +(158-x)^2$

⇒ $(130)^2=x^2+(158-x)(158-x)$

⇒ $16900=x^2+24964-158x-158x+x^2$

⇒ $16900 =2x^2-316x+24964$

⇒ $2x^2+316x+24964-16900=0$

⇒ $2x^2-316x+8064=0$

⇒ $x^2-158x+4032=0$

Applying quadratic formula;

Quadratic formula : $\frac{\pm b \sqrt{b^2-4ac} }{2a}$ where a=1 and b=-158 and c=4032

So the value of x= 126 and 32.

The length of each side of the sidewalk is 'x'= 126 m and '(158-x)'='(158-126)'=32 m

7 0

3 years ago

Please help me with this math problem :)

telo118 [61]

The correct answer is C. hope this helps

4 0

3 years ago

Suppose a student's score on a standardize test to be a continuous random variable whose distribution follows the Normal curve.

blsea [12.9K]

Answer:

a) Percentage of students scored below 300 is 1.79%.

b) Score puts someone in the 90th percentile is 638.

Step-by-step explanation:

Given : Suppose a student's score on a standardize test to be a continuous random variable whose distribution follows the Normal curve.

(a) If the average test score is 510 with a standard deviation of 100 points.

To find : What percentage of students scored below 300 ?

Solution :

Mean $\mu=510$ ,

Standard deviation $\sigma=100$

Sample mean $x=300$

Percentage of students scored below 300 is given by,

$P(Z\leq \frac{x-\mu}{\sigma})\times 100$

$=P(Z\leq \frac{300-510}{100})\times 100$

$=P(Z\leq \frac{-210}{100})\times 100$

$=P(Z\leq-2.1)\times 100$

$=0.0179\times 100$

$=1.79\%$

Percentage of students scored below 300 is 1.79%.

(b) What score puts someone in the 90th percentile?

90th percentile is such that,

$P(x\leq t)=0.90$

Now, $P(\frac{x-\mu}{\sigma} < \frac{t-\mu}{\sigma})=0.90$

$P(Z< \frac{t-\mu}{\sigma})=0.90$

$\frac{t-\mu}{\sigma}=1.28$

$\frac{t-510}{100}=1.28$

$t-510=128$

$t=128+510$

$t=638$

Score puts someone in the 90th percentile is 638.

5 0

3 years ago

Plz solve the following with steps (people who just come by without answering the question and taking the points may end up as b

sleet_krkn [62]

Answer:

<h2>12) There are 534 students who do not lunch in school.</h2>

Step-by-step explanation:

<h3>12. </h3><h3>Simple solution: </h3><h3>890 ÷ 5 = 178 </h3><h3>Therefore: 1/5 = 178 </h3><h3 /><h3>•To find the 2/5 of the students, we have to multiply 178 by 2</h3><h3>178 × 2 = 356</h3><h3>Therefore, 356 students stay to have lunch.</h3><h3 /><h3>•To find the remaining students who do not lunch in school, we have to subtract 356 to 890.</h3><h3>890 - 356 = 534</h3><h3>Therefore, there are 534 students who do not lunch in school.</h3><h3 /><h3 />

8 0

3 years ago

Which exponential function goes through the points (1,8) and (4,64)?

vova2212 [387]

Plug in (4,64) into each answer choice.

A) 4(2)^x
64 =4(2)^4
64 = 4(16)
64 = 64

Answer choice A is correct.

B) f(x) = 2(4)^x
64 = 2(4)^4
64 = 2(256)
64 ≠ 512

Answer choice B is incorrect.

C) f(x) = 4(2)^{-x}
64 = 4(2)^{-4}
64 = 4(-0.0625)
64 ≠ 0.25

Answer choice C is incorrect.

D) f(x) = 2(4)^{-x}
64 = 2(4)^{-4}
64 = 2(0.00390625)
64 ≠ 0.0078125

Answer choice D is incorrect.

Your answer is B<span>) f(x)=2(4)^x</span>

4 0

2 years ago