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2 years ago

Steven has some money if he spends nine dollars then he will have 3/5 of the amount he started with

2 answers:

7 0

X - 9 = 3/5x
x - 0.6x = 9
0.4x = 9
x = 22.5
22.5 - 9 = 13.5

Therefore, Steven will have $13.50.
Im not entirely sure. You have to recheck this with someone else. Im having a brain fart right now lol

Vesna [10]2 years ago

5 0

Total money * fraction = part
$x* \frac{3}{5} =9 \\ ( \frac{5}{3}) * \frac{3x}{5} = 9* \frac{5}{3} \\ x= \frac{45}{3} =15$

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3 years ago

A 9 pound bag of seed holds 3 pounds less than four smaller bags of seed find the weight of the smaller bag of seed

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2 years ago

Find the values of x and y for which the quadrilateral below must be a parallelogram.

Fofino [41]

Since there is no picture, find here-under the conditions that a quadrilateral becomes a parallelogram:
( All are either or)
1- opposite sides should be congruent
2- opposite angles should be congruent
3- opposite sides parallel
4-The sum of 2 adjacent angles to equal 180°
5 the 2 diagonals intersect in their middle

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2 years ago

Read 2 more answers

Perpendicular to the line y =6 - 3x; passes through (-3, -1)

madam [21]

Answer:

$y=\frac{1}{3}x$

Step-by-step explanation:

Perpendicular lines

Perpendicular lines have slopes whose product is -1. In other words, to find a line that is perpendicular to a given line, the new line must have a that is the opposite reciprocal of the original line.

Passing through a point
Additionally, if a line contains a point, then the point must be a solution to the equation (meaning, when you plug in the "x" and "y", the equation must be true).

Finding our perpendicular line

Work on slope first

To find the slope of the original line, rewrite the original line in slope-intercept form: $y=mx+b$

$y=6-3x\\y=6+(-3x)\\y=(-3x)+6\\y=-3x+6\\y=-\frac{3}{1}x+6$

In this form, the slope is the number multiplied to the "x", so the original slope is -3/1.

Thus, the slope of the new perpendicular line will be the opposite reciprocal of -3/1 ... which is 1/3.

Writing what we do know about the new perpendicular line, we have $y=\frac{1}{3}x+b$

Making sure it passes through the point
This new line is also supposed to contain the point (-3,-1), so (-3,-1) must be a solution to the equation, for whatever constant-value the "b" is. To find out the "b", substitute the known quantities, and solve:

$-1=\frac{1}{3} (-3)+b\\-1=-1+b\\(-1)+1=(-1+b)+1\\0=b$

Substituting this into our equation:

$y=\frac{1}{3}x+(0)\\y=\frac{1}{3}x$

Conclusion

So, the equation for a line that is perpendicular to the original line $y=6-3x$ , and that also passes through (-3,-1) is $y=\frac{1}{3}x$

6 0

1 year ago