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Marianna [84]
3 years ago
6

A cone resting on its base, with a dashed line from the side of the circle to the center of the circle labeled r. The edge of th

e cone is labeled Slant height (l).
The surface area of a cone is given by the formula
S = πl + πr2. Solve the formula for l.

l = S – r2
l = S + r2
l = l equals StartFraction S Over pi minus r squared. – r2
l = l equals StartFraction S Over pi plus r squared. + r2
Mathematics
2 answers:
Inessa05 [86]3 years ago
9 0

Answer:

The answer is C.

Step-by-step explanation:

Edge 2020 + top comment !

Ket [755]3 years ago
7 0

Answer:

its C (l = l equals StartFraction S Over pi minus r squared. – r2)

Step-by-step explanation:

i guessed and got it right(:

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What is the value of the digit 9 in the number 474.39?
frosja888 [35]
The value of the 3 is 3/10 and so the
9 equals 9/100


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4 years ago
Sandi lives 5 miles from her school. One day, she took the bus from her house to school. After school, she went to the library t
Fiesta28 [93]

Her house to school is 5 miles.

The distance on the map is 2.5 inches, so we know 2.5 inches equals 5 miles.

Divide 5 miles by 2.5 inches to find miles per inch:

5 / 2.5 = 2 miles per inch.

Now you can multiply the other dimensions on the map by 2 to find total miles:

School to Library = 3 x 2 = 6 miles.

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3 0
3 years ago
Read 2 more answers
6 divided by 2 (1 plus 2) equals
nadya68 [22]

Answer:

9

6 divided by 2 = 3

1 +2 = 3

3 x 3 = 9

5 0
3 years ago
Divisibility rules for 2, 5, and 10
liubo4ka [24]

Answer:

The correct answer to the question is C) 940

5 0
3 years ago
Which corresponds to the perimeter of triangle ABC?
____ [38]

Answer:

The answer to your question is: letter C

Step-by-step explanation:

Data

A (-5 , -1)

B (-2, 3)

C (6, -3)

Perimeter = ?

Formula

d = \sqrt{(x2 - x1)^{2} + (y2 - y1)^{2} }

distance AB      d = \sqrt{(-2 + 5)^{2} + (3 + 1)^{2} }

                         d = \sqrt{(3)^{2} + (4)^{2} }

                         d = \sqrt{(9 + (16) }

                                 d = \sqrt{25}

                                        d = 5

Distance BC    d = \sqrt{(-3 - 3)^{2} + (6 + 2)^{2} }

                         d = \sqrt{(-6)^{2} + (8)^{2} }

                         d = \sqrt{36 + 64}                    

                         d = \sqrt{100}

                                d = 10

Distance AC     d = \sqrt{(-3 + 1)^{2} + (6 + 5)^{2} }

                         d = \sqrt{(-2)^{2} + (11)^{2} }

                         d = \sqrt{4 + 121}

                         d = \sqrt{125}

                                d = 11.2

Perimeter = 5 + 10 + 11.2

                = 15 + \sqrt{125}

4 0
4 years ago
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