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serg [7]
3 years ago
6

A heavy rope, 30 ft long, weighs 0.4 lb/ft and hangs over the edge of a building 80 ft high. Approximate the required work by a

Riemann sum, then express the work as an integral and evaluate it.How much work W is done in pulling half the rope to the top of the building
Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
6 0

Answer:

180 fb*lb

45 ft*lb

Step-by-step explanation:

We have that the work is equal to:

W = F * d

but when the force is constant and in this case, it is changing.

 therefore it would be:

W = \int\limits^b_ a {F(x)} \, dx

Where a = 0 and b = 30.

F (x) = 0.4 * x

Therefore, we replace and we would be left with:

W = \int\limits^b_a {0.4*x} \, dx

We integrate and we have:

W = 0.4 / 2 * x ^ 2

W = 0.2 * (x ^ 2) from 0 to 30, we replace:

W = 0.2 * (30 ^ 2) - 0.2 * (0 ^ 2)

W = 180 ft * lb

Now in the second part it is the same, but the integral would be from 0 to 15.

we replace:

W = 0.2 * (15 ^ 2) - 0.2 * (0 ^ 2)

W = 45 ft * lb

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Members of the Wide Waters Club pay
vivado [14]

Answer:

The number of times members and non-members will have to rent a boat in order to pay the same amount=20

Step-by-step explanation:

We can have two expressions to show the total cost paid by a member and non-member;

Total cost by member=Cost per summer season+cost per number of times they rent a boat×number of times they rent a boat

where;

Cost per summer season=$105

Cost per number of times they rent a boat=$9.50

Number of times they rent a boat=n

Replacing;

Total cost by a member=105+(9.5×n)=9.5 n+105......equation 1

Total cost by a non-member=Cost per number of times they rent a boat×number of times they rent a boat

where;

Cost per number of times they rent a boat=$14.75

Number of times they rent a boat=n

Replacing;

Total cost by a non-member=(14.75×n)=14.75 n......equation 2

To calculate the number of times they would have to rent a boat in order to pay the same amount, we equate equation 1 to equation 2

9.5 n+105=14.75 n

14.75 n-9.5 n=105

5.25 n=105

n=105/5.25

n=20

The number of times members and non-members will have to rent a boat in order to pay the same amount=20

6 0
3 years ago
Mary has 1/4 of a tank of gas.A quarter or a tank is equal to 5 gallons how many gallons does her tank hold
Naddika [18.5K]

20 gallons

5 times 4 is 20

Hope this helps and have a great day!

7 0
3 years ago
The length of overline CD is 12 units. C^ prime D^ prime is the image of overline CD under a dilation with a scale factor of n.
Rufina [12.5K]

Answer:

A, D , and E

Step-by-step explanation:

We have that:

\overline{CD} = 12 \: units

\overline{C'D'}

is the image of CD after a dilation of scale factor n.

We use the relation between the image length and object length:

\overline{C'D'} = n \times \overline{CD}

Option A

If n=3/2, then

\overline{C'D'}  =  \frac{3}{2}  \times 12 = 3 \times 6 = 18 \: units

This is true.

Option B

If n=4, then

\overline{C'D'} = 4 \times 12 = 36 \: units

This is false.

Option C

If n=8, then

\overline{C'D'} = 8 \times 12 = 96 \: units

This too is false.

Option D

If n=2, then

\overline{C'D'} = 2 \times 12 = 24 \: units

This is true

Option E

If n=3/4, then

\overline{C'D'} =  \frac{3}{4}  \times  12

\overline{C'D'} =  3 \times 3 = 9 \: units

This is also true.

4 0
3 years ago
Use Laplace transform methods to solve the differential equation: The initial conditions are f(0) = 0 and <img src="https://tex.
Llana [10]

Answer:

Step-by-step explanation:

\frac{d^2 y}{dt^2} +12\frac{dy}{dt} +32y = 10e^{-2t} where f(x) is replaced by y

Take Laplace on both sides

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We can resolve into partial fraction to get Y = L(y)

Let this equals

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Solving we get

s=-9

24C = 10 or C =5/12

s=-2:  A=10/12=5/6

s=-4: B = -5/4

Taking inverse Laplace

y(t) = \frac{-5e^{-4t} }{4} + \frac{5e^{-8t} }{12} +\frac{-5e^{-2t} }{6}

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3 years ago
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Answer:

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