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IgorC [24]
3 years ago
10

Parallel lines need answer quickly

Mathematics
2 answers:
faust18 [17]3 years ago
8 0

Answer:

124 + x = 180 \\  \\ x = 180 - 124 \\  \\ x = 56

it's a co inter angle

they sum is 180 degree

NeTakaya3 years ago
7 0

According to above figure,

The angles 124° and x are forming pair of co- interior angles which are supplementary.

so,

  • x + 124 \degree = 180 \degree

  • x = 180\degree - 124\degree

  • x = 56\degree
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Alexus [3.1K]

Answer:

what type? if right then

7^2+16^2=23^2

49+256=529

305≠529

so its not a right triangle

Step-by-step explanation:

7 0
3 years ago
Can you help me with it
Nadya [2.5K]

Answer:

I believe it's A

1.4375

Step-by-step explanation:

100/16 = 6.25

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3 years ago
if 3/4 of a cup of water fills 2/3 of a plastic container, how many containers can you fill with one cup of water?​
Luda [366]

Answer:

1 cup of water will fill = \frac{8}{9} of the plastic container.

Step-by-step explanation:

Given :

\frac{3}{4} of a cup of water fills \frac{2}{3} of a plastic container.

To find number of containers that can be filled with 1 cup of water, we will use unitary method.

if \frac{3}{4} of a cup of water fills \frac{2}{3} of a plastic container.

Then 1 cup of water will fill = \frac{2}{3}\div \frac{3}{4} of a container.

Dividing fractions.

\frac{2}{3}\div \frac{3}{4}

Replacing division with multiplication by taking reciprocal of the divisor.

\frac{2}{3}\times \frac{4}{3}

Multiplying the numerators and denominators.

\frac{2\times4}{3\times3}

\frac{8}{9}

∴ 1 cup of water will fill = \frac{8}{9} of the plastic container.

5 0
3 years ago
Find the average squared distance between the points of r{(x,y): 0x, 0y} and the point (,)
ivolga24 [154]

The average squared distance between the points is their variance

The average squared distance is 8/3

<h3>How to determine the average squared distance?</h3>

The given parameters are:

R={(x,y): 0<=x<=2, 0<=y<=2}

The point = (2,2).

f(x,y) = (x-2)² + (y-2)²

The squared distance is calculated as:

D² = f(x,y) = (x-2)² + (y-2)²

Where the area (A) is:

A = xy

Substitute the maximum values of x and y in A = xy

A = 2 * 2

A = 4

The minimum values of x and y are 0.

So, the limits for the integrals are 0 to 2

The integral becomes

D\² = \int \int (x-2)\² + (y-2)\² dx dy

Expand

D\² = \int \int x\² -4x + 4 + (y-2)\² dx dy

Evaluate the inner integral with respect to x from 0 to 2

D\² = \int \frac 13x^3 -2x^2 + 4x + x(y-2)\² |\limits^2_0 dy

Expand

D\² = \int [\frac 13(2)^3 -2(2)^2 + 4(2) + (2)(y-2)\²] dy

Simplify

D\² = \int \frac 83 + (2)(y-2)\² dy

Expand

D\² = \int \frac 83 + 2y^2-8y + 8 \ dy

Evaluate the integral with respect to y from 0 to 2

D\² = [\frac 83y + \frac 23y^3- 4y^2 + 8y ]|\limits^2_0

Expand

D\² = \frac 83*2 + \frac 23*2^3- 4*2^2 + 8*2

D² = 32/3

The average squared distance (AD²) is calculated as:

AD² = D²/A

So, we have:

AD² = 32/3 \div 4

Evaluate the quotient

AD² = 32/12

Simplify

AD² = 8/3

Hence, the average squared distance is 8/3

Read more about average distance or variance at:

brainly.com/question/15858152

8 0
3 years ago
N is an integer such that 3n + 4 &lt; 19 and
Alekssandra [29.7K]

Answer:

Step-by-step explanation:

3n+4<19

3n<19-4

3n<15

n<5

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combining

(-∞,-16)U(16/9,5)

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