Take a look at all 3 expressions: numbers, terms, and exponents.
4, 8, and 6 all have a GCF of 2.
y^5, y^3, and y^2 have a GCF of y^2.
Therefore, the GCF is 2y^2. Removing it gets you:
2y^2(2y^3 + 4y - 3)
Answer:
(328i + 82) / 17
Step-by-step explanation:
`(2i(4+5i)(4-5i))/(4+i)
= (2i(16 - 25i^2)) / (4 + i)
= (2i( 16 + 25) )) / (4 + 1) [Note:- i^2 = -1]
= 82i / (4 + i)
= 82i(4 - i) / (4 + i)(4 - 1)
= 328i + 82 / (16 - i^2)
= (328i + 82) / 17
Hi there! Hopefully this helps!
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<em>0.77</em><em> </em><em>as a </em><u><em>fraction</em></u><em> is </em><u><em>77/100</em></u><em>.</em>
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<em>0.2904 as a </em><u><em>fraction</em></u><em> is </em><u><em>2904⁄10000</em></u><em> </em><u><em>unsimplified</em></u><em>. (Simplified would be </em><u><em>363⁄1250</em></u><em>)</em>
The answer is .I took the test so thats the answer
Answer:
−16(2−−5)
Step-by-step explanation:
hay un factor común entre estos números, por lo que simplemente −16t2+16t+80 divida y reutilice y luego reciba−162+16+80 llegar
−16(2−−5)