Answer: See explanation
Step-by-step explanation:
Total water fetched = 24 pints.
Jill drank a tenth of this. This will be:
= 1/10 × 24
= 2.4 pints
Jack drank a quarter. This will be:
= 1/4 × 24 = 6.
They gave three eighths to dame Dob . Thus will be:
= 3/8 × 24
= 9
They gave a fifth to jill's mother. This will be:
= 1/5 × 24.
= 4.80
Amount that'll be left over will be:
= 24 - (2.40 + 6 + 9 + 4.80)
= 24 - 22.2
= 1.8
1.8 pints of water will be left over.
Answer:
24.39mL of the solution would be given per hour.
Step-by-step explanation:
This problem can be solved by direct rule of three, in which there are a direct relationship between the measures, which means that the rule of three is a cross multiplication.
The first step to solve this problem is to see how many mg of the solution is administered per hour.
Each minute, 200 ug are administered. 1mg has 1000ug, so
1mg - 1000 ug
xmg - 200 ug



In each minute, 0.2 mg are administered. Each hour has 60 minutes. How many mg are administered in 60 minutes?
1 minute - 0.2 mg
60 minutes - x mg


In an hour, 12 mg of the drug is administered. In 250 mL, there is 123 mg of the drug. How many ml are there in 12 mg of the drug.
123mg - 250mL
12 mg - xmL


mL
24.39mL of the solution would be given per hour.
D) 36
7 - 3 + 5 = 9 × 4 = 36
Answer:
a) 7
b) -8.2
c) 0
d) -7
e) -1 3/4
f) 121
Step-by-step explanation:
Just put the opposite for each one. The absolute value is the distance away from 0.
Answer:

Step-by-step explanation:
This is a conditional probability exercise.
Let's name the events :
I : ''A person is infected''
NI : ''A person is not infected''
PT : ''The test is positive''
NT : ''The test is negative''
The conditional probability equation is :
Given two events A and B :
P(A/B) = P(A ∩ B) / P(B)

P(A/B) is the probability of the event A given that the event B happened
P(A ∩ B) is the probability of the event (A ∩ B)
(A ∩ B) is the event where A and B happened at the same time
In the exercise :



We are looking for P(I/PT) :
P(I/PT)=P(I∩ PT)/ P(PT)

P(PT/I)=P(PT∩ I)/P(I)
0.904=P(PT∩ I)/0.025
P(PT∩ I)=0.904 x 0.025
P(PT∩ I) = 0.0226
P(PT/NI)=0.041
P(PT/NI)=P(PT∩ NI)/P(NI)
0.041=P(PT∩ NI)/0.975
P(PT∩ NI) = 0.041 x 0.975
P(PT∩ NI) = 0.039975
P(PT) = P(PT∩ I)+P(PT∩ NI)
P(PT)= 0.0226 + 0.039975
P(PT) = 0.062575
P(I/PT) = P(PT∩I)/P(PT)
